24.5 g of CaCl2 (M = 110.98 g/mol) is dissolved in water to make 150 mL of solution. Find the molarity c.
Molarity & dilution worksheet with answers
1.Easy
m = 24.5 gM = 110.98 g/molV = 150 mL
c = mol/L
2.Easy
26.5 g of KMnO4 (M = 158.03 g/mol) is dissolved in water to make 200 mL of solution. Find the molarity c.
m = 26.5 gM = 158.03 g/molV = 200 mL
c = mol/L
3.Medium
You need 200 mL of 0.05 mol/L solution and have a 1 mol/L stock solution. What volume V1 of stock solution do you need?
c1 = 1 mol/Lc2 = 0.05 mol/LV2 = 200 mL
V1 = mL
4.Medium
You need 200 mL of 0.3 mol/L solution and have a 2.5 mol/L stock solution. What volume V1 of stock solution do you need?
c1 = 2.5 mol/Lc2 = 0.3 mol/LV2 = 200 mL
V1 = mL
5.Hard
300 mL of a 0.2 mol/L solution is mixed with 50 mL of a 3 mol/L solution of the same substance. Find the concentration c of the mixture (volumes are additive).
c1 = 0.2 mol/LV1 = 300 mLc2 = 3 mol/LV2 = 50 mL
c = mol/L
6.Hard
300 mL of a 0.8 mol/L solution is mixed with 200 mL of a 0.05 mol/L solution of the same substance. Find the concentration c of the mixture (volumes are additive).
c1 = 0.8 mol/LV1 = 300 mLc2 = 0.05 mol/LV2 = 200 mL
c = mol/L
Answer key
- 1. c = 1.472 mol/L
- 2. c = 0.8384 mol/L
- 3. V1 = 10 mL
- 4. V1 = 24 mL
- 5. c = 0.6 mol/L
- 6. c = 0.5 mol/L
Full step-by-step solutions: practise this topic on examproblems.com.