24.5 g of CuSO4 (M = 159.61 g/mol) is dissolved in water to make 150 mL of solution. Find the molarity c.
Molarity & dilution worksheet with answers
1.Easy
m = 24.5 gM = 159.61 g/molV = 150 mL
c = mol/L
2.Easy
What mass m of KNO3 (M = 101.1 g/mol) do you need to make 100 mL of a 0.1 mol/L solution?
V = 100 mLc = 0.1 mol/LM = 101.1 g/mol
m = g
3.Medium
You need 100 mL of 0.5 mol/L solution and have a 1 mol/L stock solution. What volume V1 of stock solution do you need?
c1 = 1 mol/Lc2 = 0.5 mol/LV2 = 100 mL
V1 = mL
4.Medium
You need 1000 mL of 0.25 mol/L solution and have a 5 mol/L stock solution. What volume V1 of stock solution do you need?
c1 = 5 mol/Lc2 = 0.25 mol/LV2 = 1000 mL
V1 = mL
5.Hard
50 mL of a 0.1 mol/L solution is mixed with 100 mL of a 0.05 mol/L solution of the same substance. Find the concentration c of the mixture (volumes are additive).
c1 = 0.1 mol/LV1 = 50 mLc2 = 0.05 mol/LV2 = 100 mL
c = mol/L
6.Hard
200 mL of a 0.25 mol/L solution is mixed with 100 mL of a 3 mol/L solution of the same substance. Find the concentration c of the mixture (volumes are additive).
c1 = 0.25 mol/LV1 = 200 mLc2 = 3 mol/LV2 = 100 mL
c = mol/L
Answer key
- 1. c = 1.023 mol/L
- 2. m = 1.011 g
- 3. V1 = 50 mL
- 4. V1 = 50 mL
- 5. c = 0.06667 mol/L
- 6. c = 1.167 mol/L
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