Momentum & collisions worksheet with answers

Free printable Momentum & collisions worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
0.5 kg2 m/s2 kg

A 0.5 kg trolley moving at 2 m/s runs into a 2 kg trolley at rest. After the collision the first trolley is at rest. Find the velocity v′2 of the second trolley.

m1 = 0.5 kgv1 = 2 m/sm2 = 2 kgv′1 = 0 m/s
v′2 = m/s
2.Easy
5 kg7 m/s3.5 kg

A 5 kg trolley moving at 7 m/s runs into a 3.5 kg trolley at rest. After the collision the first trolley continues in the same direction at 2.5 m/s. Find the velocity v′2 of the second trolley.

m1 = 5 kgv1 = 7 m/sm2 = 3.5 kgv′1 = 2.5 m/s
v′2 = m/s
3.Medium
1.5 kg3 m/s3.5 kg

A 1.5 kg glider moving at 3 m/s makes a perfectly elastic head-on collision with a 3.5 kg glider at rest on a frictionless track. Find the velocity v′1 of the first glider after the collision (positive in its original direction).

m1 = 1.5 kgm2 = 3.5 kgv1 = 3 m/sv2 = 0
v′1 = m/s
4.Medium
7 kg34 m/s7 kgv′2​ = ?

A 14 kg projectile moving horizontally at 24 m/s explodes into two fragments that move along the same line. The 7 kg fragment continues forwards at 34 m/s. Find the velocity v′2 of the 7 kg fragment (positive in the original direction).

M = 14 kgu = 24 m/sm1 = 7 kgv′1 = 34 m/sm2 = 7 kg
v′2 = m/s
5.Hard
2.5 kgv = ?5 g25°L = 2 m

A 5 g bullet is fired horizontally into a 2.5 kg block hanging from light strings 2 m long, and stays in it. The strings swing out to a largest angle of 25° from the vertical. Use g = 9.81 m/s². Find the speed v of the bullet before impact.

m = 5 gM = 2.5 kgL = 2 mθ = 25°g = 9.81 m/s²
v = m/s
6.Hard
1300 kg12 m/s1400 kg23 m/sv′ = ?

At a crossing a 1300 kg car travelling east at 12 m/s collides with a 1400 kg car travelling north at 23 m/s. The cars lock together. Find the speed v′ of the wreck just after the collision.

m1 = 1300 kgv1 = 12 m/s (E)m2 = 1400 kgv2 = 23 m/s (N)
v′ = m/s

Answer key

  1. 1. v′2 = 0.5 m/s
  2. 2. v′2 = 6.429 m/s
  3. 3. v′1 = −1.2 m/s
  4. 4. v′2 = 14 m/s
  5. 5. v = 960.6 m/s
  6. 6. v′ = 13.25 m/s

Full step-by-step solutions: practise this topic on examproblems.com.