1.Easy
A 1600 kg car moving at 12 m/s runs into a stationary 600 kg car. The cars lock together. Find their common velocity v′ just after the collision (positive in the first car’s direction).
m1 = 1600 kgv1 = 12 m/sm2 = 600 kgv2 = 0 m/s
v′ = m/s
Momentum & collisions worksheet with answers
2.Easy
A 3.5 kg trolley moving at 4 m/s runs into a 5 kg trolley at rest. After the collision the first trolley is at rest. Find the velocity v′2 of the second trolley.
m1 = 3.5 kgv1 = 4 m/sm2 = 5 kgv′1 = 0 m/s
v′2 = m/s
3.Medium
A 1.5 kg glider moving at 9 m/s makes a perfectly elastic head-on collision with a 2.5 kg glider at rest on a frictionless track. Find the velocity v′1 of the first glider after the collision (positive in its original direction).
m1 = 1.5 kgm2 = 2.5 kgv1 = 9 m/sv2 = 0
v′1 = m/s
4.Medium
A 1900 kg car moving at 10 m/s runs into a stationary 700 kg car and the two lock together. How much kinetic energy ΔK is lost in the collision?
m1 = 1900 kgv1 = 10 m/sm2 = 700 kgv2 = 0
ΔK = J
5.Hard
At a crossing a 900 kg car travelling east at 19 m/s collides with a 1800 kg car travelling north at 8 m/s. The cars lock together. Find the direction θ of the wreck just after the collision, measured north of east.
m1 = 900 kgv1 = 19 m/s (E)m2 = 1800 kgv2 = 8 m/s (N)
θ = °
6.Hard
An 8 g bullet is fired horizontally into a 2.5 kg block hanging from light strings 0.8 m long, and stays in it. The strings swing out to a largest angle of 20° from the vertical. Use g = 9.81 m/s². Find the speed v of the bullet before impact.
m = 8 gM = 2.5 kgL = 0.8 mθ = 20°g = 9.81 m/s²
v = m/s
Answer key
- 1. v′ = 8.727 m/s
- 2. v′2 = 2.8 m/s
- 3. v′1 = −2.25 m/s
- 4. ΔK = 25577 J
- 5. θ = 40.1 °
- 6. v = 305 m/s
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