Momentum & collisions worksheet with answers

Free printable Momentum & collisions worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
700 kg24 m/s1400 kg14 m/s

A 700 kg car moving at 24 m/s collides head-on with a 1400 kg car moving at 14 m/s in the opposite direction. The cars lock together. Find their common velocity v′ just after the collision (positive in the first car’s direction).

m1 = 700 kgv1 = 24 m/sm2 = 1400 kgv2 = −14 m/s
v′ = m/s
2.Easy
1100 kg17 m/s1800 kg9 m/s

A 1100 kg car moving at 17 m/s collides head-on with a 1800 kg car moving at 9 m/s in the opposite direction. The cars lock together. Find their common velocity v′ just after the collision (positive in the first car’s direction).

m1 = 1100 kgv1 = 17 m/sm2 = 1800 kgv2 = −9 m/s
v′ = m/s
3.Medium
1.5 kg5 m/s3 kg

A 1.5 kg glider moving at 5 m/s makes a perfectly elastic head-on collision with a 3 kg glider at rest on a frictionless track. Find the velocity v′1 of the first glider after the collision (positive in its original direction).

m1 = 1.5 kgm2 = 3 kgv1 = 5 m/sv2 = 0
v′1 = m/s
4.Medium
4 kg42 m/s3 kgv′2​ = ?

A 7 kg projectile moving horizontally at 20 m/s explodes into two fragments that move along the same line. The 4 kg fragment continues forwards at 42 m/s. Find the velocity v′2 of the 3 kg fragment (positive in the original direction).

M = 7 kgu = 20 m/sm1 = 4 kgv′1 = 42 m/sm2 = 3 kg
v′2 = m/s
5.Hard
1600 kgv1​ = ?1000 kg

A 1600 kg car runs into a parked 1000 kg car. The wrecks lock together and skid 13 m before stopping. The coefficient of kinetic friction between tyres and road is 0.7. Use g = 9.81 m/s². Find the speed v1 of the first car just before the collision.

m1 = 1600 kgm2 = 1000 kgd = 13 mμ = 0.7g = 9.81 m/s²
v1 = m/s
6.Hard
24 m/s18 m/s

A 0.2 kg ball hits a wall at 24 m/s and bounces straight back at 18 m/s. The contact lasts 50 ms. Find the average force Favg of the wall on the ball.

m = 0.2 kgvin = 24 m/svout = 18 m/sΔt = 50 ms
Favg = N

Answer key

  1. 1. v′ = −1.333 m/s
  2. 2. v′ = 0.8621 m/s
  3. 3. v′1 = −1.667 m/s
  4. 4. v′2 = −9.333 m/s
  5. 5. v1 = 21.71 m/s
  6. 6. Favg = 168 N

Full step-by-step solutions: practise this topic on examproblems.com.