For f(x, y) = −x³y − 4x² + y² + 3xy, find the partial derivative ∂f/∂x at the point (−2, −2).
Multivariable calculus worksheet with answers
1.Easy
f(x, y) = −x³y − 4x² + y² + 3xyP = (−2, −2)
fx(−2, −2) =
2.Easy
For f(x, y) = −4x²y − 3x² + 2y³ + 4xy, find the partial derivative ∂f/∂x at the point (2, 1).
f(x, y) = −4x²y − 3x² + 2y³ + 4xyP = (2, 1)
fx(2, 1) =
3.Medium
For f(x, y) = −4xy² − 4x³ + 5y³ − 3xy, find the maximum rate of change of f at the point (2, 3), that is |∇f|.
f(x, y) = −4xy² − 4x³ + 5y³ − 3xyP = (2, 3)
|∇f| =
4.Medium
For f(x, y) = xy³ + 3x² − 2y² − 3xy, find the maximum rate of change of f at the point (−2, 2), that is |∇f|.
f(x, y) = xy³ + 3x² − 2y² − 3xyP = (−2, 2)
|∇f| =
5.Hard
The integral I = ∫01.5 ∫x1.5 1/(1 + y²)² dy dx cannot be done in this order. Reverse the order of integration and evaluate it.
f = 1/(1 + y²)²0 ≤ x ≤ y ≤ 1.5
I =
6.Hard
The marked points are the critical points of f(x, y) = x³ − 27x + y² + 6y. Click the local minimum.
f(x, y) = x³ − 27x + y² + 6y
- 1A (3, −3)
- 2B (−3, −3)
Answer key
- 1. fx(−2, −2) = 34
- 2. fx(2, 1) = −24
- 3. |∇f| = 123.3
- 4. |∇f| = 27.86
- 5. I = 0.3462
- 6. A (3, −3)
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