For f(x, y) = 3 ln(x² + y²), find the partial derivative ∂f/∂y at the point (−1, −1).
Multivariable calculus worksheet with answers
1.Easy
f(x, y) = 3 ln(x² + y²)P = (−1, −1)
fy(−1, −1) =
2.Easy
For f(x, y) = 3y·e3xy, find the mixed second partial derivative ∂²f/∂x∂y at (0.5, 1).
f(x, y) = 3y·e3xyP = (0.5, 1)
fxy(0.5, 1) =
3.Medium
z = −3xy² + x² + 2y³ − 4xy with x = 2t − 1 and y = −t² − 2. Use the chain rule to find dz/dt at t = −1.
z = −3xy² + x² + 2y³ − 4xyx = 2t − 1y = −t² − 2t = −1
dz/dt =
4.Medium
For f(x, y) = −3x²y + 3x³ + 3y³ + 3xy, find the directional derivative Duf at P(−1, −2) in the direction towards Q(−5, −3).
f(x, y) = −3x²y + 3x³ + 3y³ + 3xyP = (−1, −2)Q = (−5, −3)
Duf =
5.Hard
Find the critical points of f(x, y) = x⁴ + y⁴ − 4xy, classify them, and give the value fmin of f at its local minimum.
f(x, y) = x⁴ + y⁴ − 4xy
fmin =
6.Hard
Evaluate I = ∬T (x) dA over the triangle T bounded by y = 0, x = 2 and y = x.
f = x0 ≤ x ≤ 20 ≤ y ≤ x
I =
Answer key
- 1. fy(−1, −1) = −3
- 2. fxy(0.5, 1) = 141.2
- 3. dz/dt = −18
- 4. Duf = 1.455
- 5. fmin = −2
- 6. I = 2.667
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