Evaluate I = ∫01 ∫12 (−x²y + 3) dy dx over the rectangle 0 ≤ x ≤ 1, 1 ≤ y ≤ 2.
Multivariable calculus worksheet with answers
1.Easy
f = −x²y + 30 ≤ x ≤ 11 ≤ y ≤ 2
I =
2.Easy
Evaluate I = ∫24 ∫25 (2y² + 6) dy dx over the rectangle 2 ≤ x ≤ 4, 2 ≤ y ≤ 5.
f = 2y² + 62 ≤ x ≤ 42 ≤ y ≤ 5
I =
3.Medium
z = −2xy³ − 4x² − 3y² − xy with x = −2t − 1 and y = 2t² − 1. Use the chain rule to find dz/dt at t = −1.
z = −2xy³ − 4x² − 3y² − xyx = −2t − 1y = 2t² − 1t = −1
dz/dt =
4.Medium
For f(x, y) = 2 sin(2x + 3y), find the directional derivative Duf at P(1, 1) in the direction towards Q(3, 4).
f(x, y) = 2 sin(2x + 3y)P = (1, 1)Q = (3, 4)
Duf =
5.Hard
The integral I = ∫01 ∫y1 ex² dx dy cannot be done in this order. Reverse the order of integration and evaluate it.
f = ex²0 ≤ y ≤ x ≤ 1
I =
6.Hard
Evaluate I = ∬T (4x − 2y) dA over the triangle T bounded by y = 0, x = 2 and y = 3x.
f = 4x − 2y0 ≤ x ≤ 20 ≤ y ≤ 3x
I =
Answer key
- 1. I = 2.5
- 2. I = 192
- 3. dz/dt = 74
- 4. Duf = 2.046
- 5. I = 0.8591
- 6. I = 8
Full step-by-step solutions: practise this topic on examproblems.com.