For f(x, y) = −2xey, find the mixed second partial derivative ∂²f/∂x∂y at (2, 2).
Multivariable calculus worksheet with answers
1.Easy
f(x, y) = −2xeyP = (2, 2)
fxy(2, 2) =
2.Easy
For f(x, y) = −4x²y³ − 2x³ − 5y³ − 4xy, find the second partial derivative ∂²f/∂y² at (1, −1).
f(x, y) = −4x²y³ − 2x³ − 5y³ − 4xyP = (1, −1)
fyy(1, −1) =
3.Medium
For f(x, y) = −xy³ − 3x³ − 4y² + 4xy, find the direction of steepest ascent at (3, 2) as the angle θ from the positive x-axis, in degrees between −180° and 180°.
f(x, y) = −xy³ − 3x³ − 4y² + 4xyP = (3, 2)
θ = °
4.Medium
For f(x, y) = −2xy³ − 5x³ − 5y³ − 2xy, find the directional derivative Duf at (−1, −2) in the direction of v = (4, 4).
f(x, y) = −2xy³ − 5x³ − 5y³ − 2xyP = (−1, −2)v = (4, 4)
Duf =
5.Hard
Find the critical points of f(x, y) = x⁴ + y⁴ − 4xy, classify them, and give the value fmin of f at its local minimum.
f(x, y) = x⁴ + y⁴ − 4xy
fmin =
6.Hard
f(x, y) = −x³ + 3x − y² + 4y has a critical point at (−1, 2). Compute the discriminant D = fxxfyy − fxy² there.
f(x, y) = −x³ + 3x − y² + 4yP = (−1, 2)
D =
Answer key
- 1. fxy(2, 2) = −14.78
- 2. fyy(1, −1) = 54
- 3. θ = −153.7 °
- 4. Duf = −20.51
- 5. fmin = −2
- 6. D = −12
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