Evaluate I = ∫02 ∫14 (5y + 2) dy dx over the rectangle 0 ≤ x ≤ 2, 1 ≤ y ≤ 4.
Multivariable calculus worksheet with answers
1.Easy
f = 5y + 20 ≤ x ≤ 21 ≤ y ≤ 4
I =
2.Easy
Evaluate I = ∫13 ∫25 (3y + 1) dy dx over the rectangle 1 ≤ x ≤ 3, 2 ≤ y ≤ 5.
f = 3y + 11 ≤ x ≤ 32 ≤ y ≤ 5
I =
3.Medium
For f(x, y) = xy − 3x³ + y², find the directional derivative Duf at (2, 1) in the direction of v = (−2, 3).
f(x, y) = xy − 3x³ + y²P = (2, 1)v = (−2, 3)
Duf =
4.Medium
For f(x, y) = 2 sin(3x − 3y), find the maximum rate of change of f at the point (1, −1), that is |∇f|.
f(x, y) = 2 sin(3x − 3y)P = (1, −1)
|∇f| =
5.Hard
The marked points are the critical points of f(x, y) = x³ + y³ − 3xy. Click the local minimum.
f(x, y) = x³ + y³ − 3xy
- 1A (1, 1)
- 2B (0, 0)
6.Hard
Use polar coordinates to evaluate I = ∬R e−(x² + y²) dA, where R is the upper half of the disc x² + y² ≤ 1 (y ≥ 0).
f = e−(x² + y²)0 ≤ r ≤ 10 ≤ θ ≤ π
I =
Answer key
- 1. I = 87
- 2. I = 69
- 3. Duf = 22.74
- 4. |∇f| = 8.147
- 5. A (1, 1)
- 6. I = 0.9929
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