Evaluate I = ∫14 ∫13 (3x·ey) dy dx over the rectangle 1 ≤ x ≤ 4, 1 ≤ y ≤ 3.
Multivariable calculus worksheet with answers
1.Easy
f = 3x·ey1 ≤ x ≤ 41 ≤ y ≤ 3
I =
2.Easy
Evaluate I = ∫14 ∫14 (y² + 3) dy dx over the rectangle 1 ≤ x ≤ 4, 1 ≤ y ≤ 4.
f = y² + 31 ≤ x ≤ 41 ≤ y ≤ 4
I =
3.Medium
For f(x, y) = 3y·exy, find the maximum rate of change of f at the point (0.5, −1), that is |∇f|.
f(x, y) = 3y·exyP = (0.5, −1)
|∇f| =
4.Medium
z = −3x³y³ + x³ + y³ + 2xy with x = −t + 2 and y = t² − 2. Use the chain rule to find dz/dt at t = 0.
z = −3x³y³ + x³ + y³ + 2xyx = −t + 2y = t² − 2t = 0
dz/dt =
5.Hard
The integral I = ∫01.5 ∫x1.5 ey² dy dx cannot be done in this order. Reverse the order of integration and evaluate it.
f = ey²0 ≤ x ≤ y ≤ 1.5
I =
6.Hard
The integral I = ∫02 ∫x2 sin(y²) dy dx cannot be done in this order. Reverse the order of integration and evaluate it.
f = sin(y²)0 ≤ x ≤ y ≤ 2
I =
Answer key
- 1. I = 390.8
- 2. I = 90
- 3. |∇f| = 2.034
- 4. dz/dt = −296
- 5. I = 4.244
- 6. I = 0.8268
Full step-by-step solutions: practise this topic on examproblems.com.