For f(x, y) = 3x³ey, find the partial derivative ∂f/∂x at the point (2, 0).
Multivariable calculus worksheet with answers
1.Easy
f(x, y) = 3x³eyP = (2, 0)
fx(2, 0) =
2.Easy
For f(x, y) = −4x³y³ − x³ + 3y² − xy, find the second partial derivative ∂²f/∂y² at (1, −2).
f(x, y) = −4x³y³ − x³ + 3y² − xyP = (1, −2)
fyy(1, −2) =
3.Medium
The tangent plane to z = 2x³e3y at the point where (x, y) = (2, 1) can be written as z = px + qy + c. Find c.
f(x, y) = 2x³e3y(a, b) = (2, 1)
c =
4.Medium
For f(x, y) = −4x²y + x³ − 3y³ + xy, find the direction of steepest ascent at (1, −2) as the angle θ from the positive x-axis, in degrees between −180° and 180°.
f(x, y) = −4x²y + x³ − 3y³ + xyP = (1, −2)
θ = °
5.Hard
Find the critical points of f(x, y) = x³ − 3x + y² − 4y, classify them, and give the value fmin of f at its local minimum.
f(x, y) = x³ − 3x + y² − 4y
fmin =
6.Hard
Evaluate I = ∬R xy dA, where R is the region between the parabola y = x² and the line y = x.
y = x²y = xf = xy
I =
Answer key
- 1. fx(2, 0) = 36
- 2. fyy(1, −2) = 54
- 3. c = −1607
- 4. θ = −66.45 °
- 5. fmin = −6
- 6. I = 0.04167
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