Evaluate I = ∫24 ∫24 (5y² + 1) dy dx over the rectangle 2 ≤ x ≤ 4, 2 ≤ y ≤ 4.
Multivariable calculus worksheet with answers
1.Easy
f = 5y² + 12 ≤ x ≤ 42 ≤ y ≤ 4
I =
2.Easy
Evaluate I = ∫13 ∫03 (2x·e−y) dy dx over the rectangle 1 ≤ x ≤ 3, 0 ≤ y ≤ 3.
f = 2x·e−y1 ≤ x ≤ 30 ≤ y ≤ 3
I =
3.Medium
The tangent plane to z = 3x³y² − 3x² at the point where (x, y) = (−1, −2) can be written as z = px + qy + c. Find c.
f(x, y) = 3x³y² − 3x²(a, b) = (−1, −2)
c =
4.Medium
z = 2 sin(x + 2y) with x = −t and y = −2t² + 2. Use the chain rule to find dz/dt at t = 1.
z = 2 sin(x + 2y)x = −ty = −2t² + 2t = 1
dz/dt =
5.Hard
f(x, y) = x³ − 12x + y² + 2y has a critical point at (−2, −1). Compute the discriminant D = fxxfyy − fxy² there.
f(x, y) = x³ − 12x + y² + 2yP = (−2, −1)
D =
6.Hard
f(x, y) = 2x² + 5xy + 2y² − 3x − 6y − 3 has a critical point at (2, −1). Compute the discriminant D = fxxfyy − fxy² there.
f(x, y) = 2x² + 5xy + 2y² − 3x − 6y − 3P = (2, −1)
D =
Answer key
- 1. I = 190.7
- 2. I = 7.602
- 3. c = 51
- 4. dz/dt = −9.725
- 5. D = −24
- 6. D = −9
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