Normal distribution worksheet with answers

Free printable Normal distribution worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
750 gσ = ?X + Y

X and Y are independent normal variables for the mass of a filled jar: jar plus contents: X has mean 250 g and standard deviation 4 g, Y has mean 500 g and standard deviation 9 g. Find the standard deviation σ of X + Y.

μX = 250 g, σX = 4 gμY = 500 g, σY = 9 g
σ = g
2.Easy
−3−2−10123zshaded area to the left of z = 0.1539

Drag z so that the shaded area under the standard normal curve, to the left of z, is 0.1539. Find z to two decimals.

A = 0.1539
z =
3.Medium
850 kg812.1 kgT = X₁ + … + X₁₀?

The masses of passengers with luggage are independent and normal with mean 85 kg and standard deviation 12 kg. Find the probability P that the total mass of 10 of them is below 812.1 kg. Round z to two decimals.

μ = 85 kgσ = 12 kgn = 10< 812.1 kg
P =
4.Medium
244.25257.75P = ?

The bag weights are normally distributed with mean 250 g and standard deviation 5 g. What fraction lies between 244.25 and 257.75 g? Give P as a decimal.

μ = 250σ = 5x1 = 244.25x2 = 257.75
P =
5.Hard
157164171178185192199cmbottom 90%

The heights of adult men are normally distributed with mean 178 cm and standard deviation 7 cm. Drag the cut-off so the shaded bottom 90% is to the left of it. Find the cut-off x.

μ = 178 cmσ = 7 cm90%
x = cm
6.Hard
0.04 mm0D − d?

Hole diameters D are normal with mean 25.04 mm and standard deviation 0.015 mm. Shaft diameters d are independent and normal with mean 25 mm and standard deviation 0.015 mm. A randomly chosen shaft fits when D − d > 0. Find the probability P that it fits. Round z to two decimals.

hole: μ = 25.04 mm, σ = 0.015 mmshaft: μ = 25 mm, σ = 0.015 mm
P =

Answer key

  1. 1. σ = 9.849 g
  2. 2. z = −1.02
  3. 3. P = 0.1587
  4. 4. P = 0.8144
  5. 5. x = 187 cm
  6. 6. P = 0.9706

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