Normal distribution worksheet with answers

Free printable Normal distribution worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
750 gσ = ?X + Y

X and Y are independent normal variables for the mass of a filled jar: jar plus contents: X has mean 250 g and standard deviation 4 g, Y has mean 500 g and standard deviation 9 g. Find the standard deviation σ of X + Y.

μX = 250 g, σX = 4 gμY = 500 g, σY = 9 g
σ = g
2.Easy
−3−2−10123zshaded area to the left of z = 0.9357

Drag z so that the shaded area under the standard normal curve, to the left of z, is 0.9357. Find z to two decimals.

A = 0.9357
z =
3.Medium
1020 kg999.2 kgT = X₁ + … + X₁₂?

The masses of passengers with luggage are independent and normal with mean 85 kg and standard deviation 12 kg. Find the probability P that the total mass of 12 of them exceeds 999.2 kg. Round z to two decimals.

μ = 85 kgσ = 12 kgn = 12> 999.2 kg
P =
4.Medium
750 g745.1 gX + Y?

X is normal with mean 250 g and standard deviation 4 g; Y is independent and normal with mean 500 g and standard deviation 9 g. Find the probability P that X + Y is more than 745.1 g. Round z to two decimals.

μX = 250, σX = 4μY = 500, σY = 9X + Y > 745.1 g
P =
5.Hard
157164171178185192199cmbottom 5%

The heights of adult men are normally distributed with mean 178 cm and standard deviation 7 cm. Drag the cut-off so the shaded bottom 5% is to the left of it. Find the cut-off x.

μ = 178 cmσ = 7 cm5%
x = cm
6.Hard
0.05 mm0D − d?

Hole diameters D are normal with mean 25.05 mm and standard deviation 0.02 mm. Shaft diameters d are independent and normal with mean 25 mm and standard deviation 0.01 mm. A randomly chosen shaft fits when D − d > 0. Find the probability P that it fits. Round z to two decimals.

hole: μ = 25.05 mm, σ = 0.02 mmshaft: μ = 25 mm, σ = 0.01 mm
P =

Answer key

  1. 1. σ = 9.849 g
  2. 2. z = 1.52
  3. 3. P = 0.6915
  4. 4. P = 0.6915
  5. 5. x = 166.5 cm
  6. 6. P = 0.9875

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