Use linear interpolation in the table to estimate the value x where y = 1.2409.
Numerical methods worksheet with answers
1.Easy
y = 1.2409
x =
2.Easy
Use the bisection method on f(x) = x² − 3 with the starting interval [1, 2]. Find the midpoint c4 of step 4.
f(x) = x² − 3[a, b] = [1, 2]n = 4
c4 =
3.Medium
Approximate ∫02 x³ dx with the trapezoid rule, n = 2, and compare it with the exact value. Find the absolute error |E| = |T − I|.
f(x) = x³[a, b] = [0, 2]n = 2
|E| =
4.Medium
Approximate ∫02 √x·e−x dx with Simpson's rule using n = 6 strips. Give S.
f(x) = √x·e−x[a, b] = [0, 2]n = 6
S =
5.Hard
Take one step of the classical Runge–Kutta method (RK4) with h = 0.5 for y′ = cos t − y, y(0) = 1. Find y₁ ≈ y(0.5).
y′ = cos t − yy(0) = 1h = 0.5
y1 =
6.Hard
Use Euler's method with h = 0.25 for y′ = t − y, y(0) = 3 to estimate y4 ≈ y(1).
y′ = t − yy(0) = 3h = 0.25
y4 =
Answer key
- 1. x = 1.46
- 2. c4 = 1.688
- 3. |E| = 1
- 4. S = 0.6378
- 5. y1 = 0.9817
- 6. y4 = 1.266
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