Use the bisection method on f(x) = x³ + 2x − 2 with the starting interval [0, 2]. Find the midpoint c3 of step 3.
Numerical methods worksheet with answers
1.Easy
f(x) = x³ + 2x − 2[a, b] = [0, 2]n = 3
c3 =
2.Easy
Use linear interpolation in the table to estimate the value x where y = 1.6761.
y = 1.6761
x =
3.Medium
Approximate ∫03 sin x dx with the trapezoid rule, n = 2, and compare it with the exact value. Find the absolute error |E| = |T − I|.
f(x) = sin x[a, b] = [0, 3]n = 2
|E| =
4.Medium
Approximate ∫01.5 √(1 + x³) dx with the trapezoid rule using n = 5 strips. Give T.
f(x) = √(1 + x³)[a, b] = [0, 1.5]n = 5
T =
5.Hard
Take one step of the classical Runge–Kutta method (RK4) with h = 0.5 for y′ = cos t − y, y(0) = 0.5. Find y₁ ≈ y(0.5).
y′ = cos t − yy(0) = 0.5h = 0.5
y1 =
6.Hard
Use Euler's method with h = 0.5 for y′ = 1 + sin(ty), y(0) = 0 to estimate y5 ≈ y(2.5).
y′ = 1 + sin(ty)y(0) = 0h = 0.5
y5 =
Answer key
- 1. c3 = 0.75
- 2. x = 3.35
- 3. |E| = 0.3879
- 4. T = 1.989
- 5. y1 = 0.6783
- 6. y5 = 2.643
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