Use linear interpolation in the table to estimate the value x where y = 1.5228.
Numerical methods worksheet with answers
1.Easy
y = 1.5228
x =
2.Easy
Apply Newton–Raphson to f(x) = x³ + 2x − 10 with the starting value x₀ = 1. Find x2.
f(x) = x³ + 2x − 10f′(x) = 3x² + 2x₀ = 1
x2 =
3.Medium
The trapezoid rule is used for ∫01 eˣ dx. The error is at most (b − a)³·M/(12n²) with M = max|f″| on [0, 1]. Find the smallest number of strips n that guarantees an error below 0.0005.
f(x) = eˣ[a, b] = [0, 1]ε = 0.0005
n =
4.Medium
Approximate ∫01 x³ dx with the trapezoid rule, n = 4, and compare it with the exact value. Find the absolute error |E| = |T − I|.
f(x) = x³[a, b] = [0, 1]n = 4
|E| =
5.Hard
Use Heun's method (improved Euler) with h = 0.1 for y′ = e−ty, y(0) = 1 to estimate y2 ≈ y(0.2).
y′ = e−tyy(0) = 1h = 0.1
y2 =
6.Hard
Use Heun's method (improved Euler) with h = 0.1 for y′ = 1 + sin(ty), y(0) = 0 to estimate y2 ≈ y(0.2).
y′ = 1 + sin(ty)y(0) = 0h = 0.1
y2 =
Answer key
- 1. x = 1.32
- 2. x2 = 1.953
- 3. n = 22
- 4. |E| = 0.01563
- 5. y2 = 1.179
- 6. y2 = 0.203
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