Op-amp circuits worksheet with answers

Free printable Op-amp circuits worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
−+Vout​Rf​ = 100 kΩVin​ = 0.6 VR1​ = 22 kΩ

The circuit is an inverting amplifier. The op-amp is ideal and runs from ±15 V supplies; its output saturates at ±14 V. Find the output voltage Vout.

Vin = 0.6 VR1 = 22 kΩRf = 100 kΩVsat = ±14 V
Vout = V
2.Easy
−+Vout​Rf​ = 4.7 kΩVin​ = 0.4 VR1​ = 1 kΩ

The op-amp is ideal and runs from ±15 V supplies. Find the output voltage Vout.

Vin = 0.4 VR1 = 1 kΩRf = 4.7 kΩ
Vout = V
3.Medium
−+Vout​Rf​ = 47 kΩVin​R1​ = 2 kΩ

The op-amp is ideal and runs from ±15 V supplies; its output saturates at ±12 V. The inverting amplifier is driven by a sine wave. Find the largest input amplitude Vin,max (peak value) for which the output does not clip.

R1 = 2 kΩRf = 47 kΩVsat = ±12 V
Vin,max = V
4.Medium
−+Vout​Rf​ = 4.7 kΩVin​R1​ = 2 kΩ

The op-amp is ideal and runs from ±15 V supplies; its output saturates at ±14 V. The inverting amplifier is driven by a sine wave. Find the largest input amplitude Vin,max (peak value) for which the output does not clip.

R1 = 2 kΩRf = 4.7 kΩVsat = ±14 V
Vin,max = V
5.Hard
−+Vout​C = 4.7 µFVin​ = −1.8 VR = 1 kΩ

The integrator uses an ideal op-amp with ±15 V supplies; its output saturates at ±14 V. The capacitor is uncharged when a constant input Vin = −1.8 V is applied at t = 0. Find the output voltage Vout at t = 10 ms.

Vin = −1.8 VR = 1 kΩC = 4.7 µFVsat = ±14 Vt = 10 ms
Vout = V
6.Hard
−+Vout​R2​ = 4.7 kΩV1​ = −1.7 VR1​ = 47 kΩV2​ = 1.1 VR3​ = 4.7 kΩR4​ = 22 kΩ

The op-amp is ideal and runs from ±15 V supplies. The resistor ratios are not matched. Find the output voltage Vout.

V1 = −1.7 VV2 = 1.1 VR1 = 47 kΩR2 = 4.7 kΩR3 = 4.7 kΩR4 = 22 kΩ
Vout = V

Answer key

  1. 1. Vout = −2.727 V
  2. 2. Vout = −1.88 V
  3. 3. Vin,max = 0.5106 V
  4. 4. Vin,max = 5.957 V
  5. 5. Vout = 3.83 V
  6. 6. Vout = 1.167 V

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