Op-amp circuits worksheet with answers

Free printable Op-amp circuits worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
−+Vout​7 VRs​ = 47 kΩRL​10 kΩ

A sensor behaves like a 7 V source with an internal resistance Rs = 47 kΩ. It feeds a load RL = 10 kΩ through an ideal voltage follower (unity-gain buffer). For comparison, find the load voltage VL if the load were connected directly to the sensor without the buffer.

Vs = 7 VRs = 47 kΩRL = 10 kΩ
VL = V
2.Easy
−+Vout​Rf​ = 22 kΩVin​R1​ = ?

An inverting amplifier with an ideal op-amp must have a voltage gain of −20. The feedback resistor is Rf = 22 kΩ. Find the input resistor R1.

Av = −20Rf = 22 kΩ
R1 = kΩ
3.Medium
−+Vout​Rf​ = ?R1​ = 10 kΩVin​

Choose the feedback resistor Rf that gives this non-inverting amplifier a voltage gain of 15.

R1 = 10 kΩAv = 15
Rf = kΩ
4.Medium
−+Vout​R2​ = 1 kΩV1​ = 0.1 VR1​ = 4.7 kΩV2​ = 1.1 VR3​ = 4.7 kΩR4​ = 1 kΩ

The difference amplifier uses an ideal op-amp with ±15 V supplies, with R3 = R1 and R4 = R2. Find the output voltage Vout.

V1 = 0.1 VV2 = 1.1 VR1 = R3 = 4.7 kΩR2 = R4 = 1 kΩ
Vout = V
5.Hard
−+Vout​Rf​ = 4.7 kΩV1​ = 1.9 VR1​ = 47 kΩV2​ = −1.3 VR2​ = 1 kΩ

The summing amplifier uses an ideal op-amp with ±15 V supplies. Find the output voltage Vout.

V1 = 1.9 VV2 = −1.3 VR1 = 47 kΩR2 = 1 kΩRf = 4.7 kΩ
Vout = V
6.Hard
−+Vout​C = 0.22 µFVin​ = 1 VR = 10 kΩ

The integrator uses an ideal op-amp with ±15 V supplies; its output saturates at ±13 V. The capacitor is uncharged when a constant input Vin = 1 V is applied at t = 0. How long after t = 0 does the output reach saturation? Find t.

Vin = 1 VR = 10 kΩC = 0.22 µFVsat = ±13 V
t = ms

Answer key

  1. 1. VL = 1.228 V
  2. 2. R1 = 1.1 kΩ
  3. 3. Rf = 140 kΩ
  4. 4. Vout = 0.2128 V
  5. 5. Vout = 5.92 V
  6. 6. t = 28.6 ms

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