A sensor behaves like a 7 V source with an internal resistance Rs = 47 kΩ. It feeds a load RL = 10 kΩ through an ideal voltage follower (unity-gain buffer). For comparison, find the load voltage VL if the load were connected directly to the sensor without the buffer.
Op-amp circuits worksheet with answers
1.Easy
Vs = 7 VRs = 47 kΩRL = 10 kΩ
VL = V
2.Easy
An inverting amplifier with an ideal op-amp must have a voltage gain of −20. The feedback resistor is Rf = 22 kΩ. Find the input resistor R1.
Av = −20Rf = 22 kΩ
R1 = kΩ
3.Medium
Choose the feedback resistor Rf that gives this non-inverting amplifier a voltage gain of 15.
R1 = 10 kΩAv = 15
Rf = kΩ
4.Medium
The difference amplifier uses an ideal op-amp with ±15 V supplies, with R3 = R1 and R4 = R2. Find the output voltage Vout.
V1 = 0.1 VV2 = 1.1 VR1 = R3 = 4.7 kΩR2 = R4 = 1 kΩ
Vout = V
5.Hard
The summing amplifier uses an ideal op-amp with ±15 V supplies. Find the output voltage Vout.
V1 = 1.9 VV2 = −1.3 VR1 = 47 kΩR2 = 1 kΩRf = 4.7 kΩ
Vout = V
6.Hard
The integrator uses an ideal op-amp with ±15 V supplies; its output saturates at ±13 V. The capacitor is uncharged when a constant input Vin = 1 V is applied at t = 0. How long after t = 0 does the output reach saturation? Find t.
Vin = 1 VR = 10 kΩC = 0.22 µFVsat = ±13 V
t = ms
Answer key
- 1. VL = 1.228 V
- 2. R1 = 1.1 kΩ
- 3. Rf = 140 kΩ
- 4. Vout = 0.2128 V
- 5. Vout = 5.92 V
- 6. t = 28.6 ms
Full step-by-step solutions: practise this topic on examproblems.com.