Op-amp circuits worksheet with answers

Free printable Op-amp circuits worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
−+Vout​Rf​ = 47 kΩVin​ = −0.7 VR1​ = 4.7 kΩ

The op-amp is ideal and runs from ±15 V supplies. Find the output voltage Vout.

Vin = −0.7 VR1 = 4.7 kΩRf = 47 kΩ
Vout = V
2.Easy
−+Vout​Rf​ = 47 kΩVin​ = 0.5 VR1​ = 10 kΩI1​

The op-amp is ideal and runs from ±15 V supplies. Find the current I1 through R₁, flowing towards the op-amp.

Vin = 0.5 VR1 = 10 kΩRf = 47 kΩ
I1 = mA
3.Medium
−+Vout​Rf​ = ?R1​ = 4.7 kΩVin​

Choose the feedback resistor Rf that gives this non-inverting amplifier a voltage gain of 10.

R1 = 4.7 kΩAv = 10
Rf = kΩ
4.Medium
−+Vout​Rf​ = 47 kΩR1​ = 10 kΩVin​

The op-amp is ideal and runs from ±15 V supplies; its output saturates at ±13 V. The non-inverting amplifier is driven by a sine wave. Find the largest input amplitude Vin,max (peak value) for which the output does not clip.

R1 = 10 kΩRf = 47 kΩVsat = ±13 V
Vin,max = V
5.Hard
−+Vout​C = 2.2 µFVin​ = 1.7 VR = 4.7 kΩ

The integrator uses an ideal op-amp with ±15 V supplies; its output saturates at ±12 V. The capacitor is uncharged when a constant input Vin = 1.7 V is applied at t = 0. Find the output voltage Vout at t = 5 ms.

Vin = 1.7 VR = 4.7 kΩC = 2.2 µFVsat = ±12 Vt = 5 ms
Vout = V
6.Hard
−+Vout​Rf​ = 47 kΩV1​ = −0.4 VR1​ = 10 kΩV2​ = −0.3 VR2​ = 4.7 kΩIf​

The summing amplifier uses an ideal op-amp with ±15 V supplies. Find the current If through the feedback resistor, flowing towards the output.

V1 = −0.4 VV2 = −0.3 VR1 = 10 kΩR2 = 4.7 kΩRf = 47 kΩ
If = mA

Answer key

  1. 1. Vout = 7 V
  2. 2. I1 = 0.05 mA
  3. 3. Rf = 42.3 kΩ
  4. 4. Vin,max = 2.281 V
  5. 5. Vout = −0.8221 V
  6. 6. If = −0.1038 mA

Full step-by-step solutions: practise this topic on examproblems.com.