Op-amp circuits worksheet with answers

Free printable Op-amp circuits worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
−+Vout​1.5 VRs​ = 4.7 kΩRL​2.2 kΩ

A sensor behaves like a 1.5 V source with an internal resistance Rs = 4.7 kΩ. It feeds a load RL = 2.2 kΩ through an ideal voltage follower (unity-gain buffer). For comparison, find the load voltage VL if the load were connected directly to the sensor without the buffer.

Vs = 1.5 VRs = 4.7 kΩRL = 2.2 kΩ
VL = V
2.Easy
−+Vout​Rf​ = 47 kΩVin​ = −1.3 VR1​ = 2 kΩ

The circuit is an inverting amplifier. The op-amp is ideal and runs from ±15 V supplies; its output saturates at ±12 V. Find the output voltage Vout.

Vin = −1.3 VR1 = 2 kΩRf = 47 kΩVsat = ±12 V
Vout = V
3.Medium
−+Vout​Rf​ = 22 kΩR1​ = 2 kΩVin​ = 0.5 V

The op-amp is ideal and runs from ±15 V supplies. Find the output voltage Vout.

Vin = 0.5 VR1 = 2 kΩRf = 22 kΩ
Vout = V
4.Medium
−+Vout​Rf​ = ?R1​ = 4.7 kΩVin​

Choose the feedback resistor Rf that gives this non-inverting amplifier a voltage gain of 11.

R1 = 4.7 kΩAv = 11
Rf = kΩ
5.Hard
Vin​V1​Vout​stage 1: invertingR1​ = 1 kΩRf1​ = 4.7 kΩstage 2: non-invertingR2​ = 22 kΩRf2​ = 10 kΩ

Two ideal op-amp stages are connected in cascade: an inverting amplifier (R1, Rf1) followed by a non-inverting amplifier (R2 to ground, Rf2 in the feedback). Both run from ±15 V supplies. The input is Vin = −0.5 V. Find the output voltage Vout.

R1 = 1 kΩRf1 = 4.7 kΩR2 = 22 kΩRf2 = 10 kΩVin = −0.5 V
Vout = V
6.Hard
−+Vout​R2​ = 10 kΩV1​ = 0.4 VR1​ = 2 kΩV2​ = −0.2 VR3​ = 4.7 kΩR4​ = 4.7 kΩ

The op-amp is ideal and runs from ±15 V supplies. The resistor ratios are not matched. Find the output voltage Vout.

V1 = 0.4 VV2 = −0.2 VR1 = 2 kΩR2 = 10 kΩR3 = 4.7 kΩR4 = 4.7 kΩ
Vout = V

Answer key

  1. 1. VL = 0.4783 V
  2. 2. Vout = 12 V
  3. 3. Vout = 6 V
  4. 4. Rf = 47 kΩ
  5. 5. Vout = 3.418 V
  6. 6. Vout = −2.6 V

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