Op-amp circuits worksheet with answers

Free printable Op-amp circuits worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
−+Vout​Rf​ = 4.7 kΩVin​ = −1.3 VR1​ = 2 kΩ

The op-amp is ideal and runs from ±15 V supplies. Find the output voltage Vout.

Vin = −1.3 VR1 = 2 kΩRf = 4.7 kΩ
Vout = V
2.Easy
−+Vout​Rf​ = 100 kΩVin​ = −1.9 VR1​ = 1 kΩ

The circuit is an inverting amplifier. The op-amp is ideal and runs from ±15 V supplies; its output saturates at ±12 V. Find the output voltage Vout.

Vin = −1.9 VR1 = 1 kΩRf = 100 kΩVsat = ±12 V
Vout = V
3.Medium
−+Vout​R2​ = 4.7 kΩV1​ = 2.1 VR1​ = 10 kΩV2​ = −0.2 VR3​ = 10 kΩR4​ = 4.7 kΩ

The difference amplifier uses an ideal op-amp with ±15 V supplies, with R3 = R1 and R4 = R2. Find the voltage V− at the inverting input.

V1 = 2.1 VV2 = −0.2 VR1 = R3 = 10 kΩR2 = R4 = 4.7 kΩ
V− = V
4.Medium
−+Vout​Rf​ = ?R1​ = 47 kΩVin​

Choose the feedback resistor Rf that gives this non-inverting amplifier a voltage gain of 51.

R1 = 47 kΩAv = 51
Rf = kΩ
5.Hard
−+Vout​C = 0.22 µFVin​ = −0.4 VR = 47 kΩ

The integrator uses an ideal op-amp with ±15 V supplies; its output saturates at ±12 V. The capacitor is uncharged when a constant input Vin = −0.4 V is applied at t = 0. Find the output voltage Vout at t = 20 ms.

Vin = −0.4 VR = 47 kΩC = 0.22 µFVsat = ±12 Vt = 20 ms
Vout = V
6.Hard
−+Vout​C = 0.47 µFVin​ = 1.4 VR = 22 kΩ

The integrator uses an ideal op-amp with ±15 V supplies; its output saturates at ±12 V. The capacitor is uncharged when a constant input Vin = 1.4 V is applied at t = 0. How long after t = 0 does the output reach saturation? Find t.

Vin = 1.4 VR = 22 kΩC = 0.47 µFVsat = ±12 V
t = ms

Answer key

  1. 1. Vout = 3.055 V
  2. 2. Vout = 12 V
  3. 3. V− = −0.06395 V
  4. 4. Rf = 2350 kΩ
  5. 5. Vout = 0.7737 V
  6. 6. t = 88.63 ms

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