Op-amp circuits worksheet with answers

Free printable Op-amp circuits worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
−+Vout​Rf​ = 4.7 kΩVin​ = 0.4 VR1​ = 1 kΩ

The op-amp is ideal and runs from ±15 V supplies. Find the output voltage Vout.

Vin = 0.4 VR1 = 1 kΩRf = 4.7 kΩ
Vout = V
2.Easy
−+Vout​8.5 VRs​ = 1 kΩRL​4.7 kΩ

A sensor behaves like an 8.5 V source with an internal resistance Rs = 1 kΩ. It feeds a load RL = 4.7 kΩ through an ideal voltage follower (unity-gain buffer). For comparison, find the load voltage VL if the load were connected directly to the sensor without the buffer.

Vs = 8.5 VRs = 1 kΩRL = 4.7 kΩ
VL = V
3.Medium
−+Vout​R2​ = 10 kΩV1​ = −2.3 VR1​ = 22 kΩV2​ = 1.8 VR3​ = 22 kΩR4​ = 10 kΩ

The difference amplifier uses an ideal op-amp with ±15 V supplies, with R3 = R1 and R4 = R2. Find the voltage V− at the inverting input.

V1 = −2.3 VV2 = 1.8 VR1 = R3 = 22 kΩR2 = R4 = 10 kΩ
V− = V
4.Medium
−+Vout​Rf​ = ?R1​ = 100 kΩVin​

Choose the feedback resistor Rf that gives this non-inverting amplifier a voltage gain of 2.

R1 = 100 kΩAv = 2
Rf = kΩ
5.Hard
−+Vout​R2​ = 2 kΩV1​ = 2 VR1​ = 47 kΩV2​ = −0.9 VR3​ = 22 kΩR4​ = 10 kΩ

The op-amp is ideal and runs from ±15 V supplies. The resistor ratios are not matched. Find the output voltage Vout.

V1 = 2 VV2 = −0.9 VR1 = 47 kΩR2 = 2 kΩR3 = 22 kΩR4 = 10 kΩ
Vout = V
6.Hard
−+Vout​C = 0.47 µFVin​ = 0.7 VR = 4.7 kΩ

The integrator uses an ideal op-amp with ±15 V supplies; its output saturates at ±12 V. The capacitor is uncharged when a constant input Vin = 0.7 V is applied at t = 0. Find the output voltage Vout at t = 5 ms.

Vin = 0.7 VR = 4.7 kΩC = 0.47 µFVsat = ±12 Vt = 5 ms
Vout = V

Answer key

  1. 1. Vout = −1.88 V
  2. 2. VL = 7.009 V
  3. 3. V− = 0.5625 V
  4. 4. Rf = 100 kΩ
  5. 5. Vout = −0.3783 V
  6. 6. Vout = −1.584 V

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