Op-amp circuits worksheet with answers

Free printable Op-amp circuits worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
−+Vout​Rf​ = 47 kΩVin​ = −1.2 VR1​ = 22 kΩ

The circuit is an inverting amplifier. The op-amp is ideal and runs from ±15 V supplies; its output saturates at ±13 V. Find the output voltage Vout.

Vin = −1.2 VR1 = 22 kΩRf = 47 kΩVsat = ±13 V
Vout = V
2.Easy
−+Vout​9 VRs​ = 4.7 kΩRL​0.47 kΩIL​

A sensor behaves like a 9 V source with an internal resistance Rs = 4.7 kΩ. It feeds a load RL = 0.47 kΩ through an ideal voltage follower (unity-gain buffer). Find the load current IL supplied by the op-amp output.

Vs = 9 VRs = 4.7 kΩRL = 0.47 kΩ
IL = mA
3.Medium
−+Vout​Rf​ = 1 kΩR1​ = 1 kΩVin​ = −2 V

The op-amp is ideal and runs from ±15 V supplies. Find the output voltage Vout.

Vin = −2 VR1 = 1 kΩRf = 1 kΩ
Vout = V
4.Medium
−+Vout​R2​ = 22 kΩV1​ = 1.2 VR1​ = 2 kΩV2​ = 0.6 VR3​ = 2 kΩR4​ = 22 kΩ

The difference amplifier uses an ideal op-amp with ±15 V supplies, with R3 = R1 and R4 = R2. Find the output voltage Vout.

V1 = 1.2 VV2 = 0.6 VR1 = R3 = 2 kΩR2 = R4 = 22 kΩ
Vout = V
5.Hard
−+Vout​Rf​ = 100 kΩV1​ = 1.5 VR1​ = 47 kΩV2​ = 0.6 VR2​ = 100 kΩ

The summing amplifier uses an ideal op-amp with ±15 V supplies. Find the output voltage Vout.

V1 = 1.5 VV2 = 0.6 VR1 = 47 kΩR2 = 100 kΩRf = 100 kΩ
Vout = V
6.Hard
Vin​V1​Vout​stage 1: invertingR1​ = 2 kΩRf1​ = 4.7 kΩstage 2: non-invertingR2​ = 4.7 kΩRf2​ = 22 kΩ

Two ideal op-amp stages are connected in cascade: an inverting amplifier (R1, Rf1) followed by a non-inverting amplifier (R2 to ground, Rf2 in the feedback). Both run from ±15 V supplies. The input is Vin = 0.6 V. Find the output voltage Vout.

R1 = 2 kΩRf1 = 4.7 kΩR2 = 4.7 kΩRf2 = 22 kΩVin = 0.6 V
Vout = V

Answer key

  1. 1. Vout = 2.564 V
  2. 2. IL = 19.15 mA
  3. 3. Vout = −4 V
  4. 4. Vout = −6.6 V
  5. 5. Vout = −3.791 V
  6. 6. Vout = −8.01 V

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