Op-amp circuits worksheet with answers

Free printable Op-amp circuits worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
−+Vout​1 VRs​ = 22 kΩRL​2.2 kΩ

A sensor behaves like a 1 V source with an internal resistance Rs = 22 kΩ. It feeds a load RL = 2.2 kΩ through an ideal voltage follower (unity-gain buffer). For comparison, find the load voltage VL if the load were connected directly to the sensor without the buffer.

Vs = 1 VRs = 22 kΩRL = 2.2 kΩ
VL = V
2.Easy
−+Vout​Rf​ = 100 kΩVin​ = −0.4 VR1​ = 10 kΩ

The op-amp is ideal and runs from ±15 V supplies. Find the output voltage Vout.

Vin = −0.4 VR1 = 10 kΩRf = 100 kΩ
Vout = V
3.Medium
−+Vout​Rf​ = 100 kΩVin​R1​ = 4.7 kΩ

The op-amp is ideal and runs from ±15 V supplies; its output saturates at ±14 V. The inverting amplifier is driven by a sine wave. Find the largest input amplitude Vin,max (peak value) for which the output does not clip.

R1 = 4.7 kΩRf = 100 kΩVsat = ±14 V
Vin,max = V
4.Medium
−+Vout​Rf​ = ?R1​ = 100 kΩVin​

Choose the feedback resistor Rf that gives this non-inverting amplifier a voltage gain of 51.

R1 = 100 kΩAv = 51
Rf = kΩ
5.Hard
−+Vout​Rf​ = 22 kΩV1​ = 1.4 VR1​ = 4.7 kΩV2​ = −1 VR2​ = 100 kΩ

The summing amplifier uses an ideal op-amp with ±15 V supplies. Find the output voltage Vout.

V1 = 1.4 VV2 = −1 VR1 = 4.7 kΩR2 = 100 kΩRf = 22 kΩ
Vout = V
6.Hard
−+Vout​R2​ = 47 kΩV1​ = 0.9 VR1​ = 22 kΩV2​ = 1.1 VR3​ = 4.7 kΩR4​ = 22 kΩ

The op-amp is ideal and runs from ±15 V supplies. The resistor ratios are not matched. Find the output voltage Vout.

V1 = 0.9 VV2 = 1.1 VR1 = 22 kΩR2 = 47 kΩR3 = 4.7 kΩR4 = 22 kΩ
Vout = V

Answer key

  1. 1. VL = 0.09091 V
  2. 2. Vout = 4 V
  3. 3. Vin,max = 0.658 V
  4. 4. Rf = 5000 kΩ
  5. 5. Vout = −6.333 V
  6. 6. Vout = 0.92 V

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