Op-amp circuits worksheet with answers

Free printable Op-amp circuits worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
−+Vout​9.5 VRs​ = 10 kΩRL​0.47 kΩIL​

A sensor behaves like a 9.5 V source with an internal resistance Rs = 10 kΩ. It feeds a load RL = 0.47 kΩ through an ideal voltage follower (unity-gain buffer). Find the load current IL supplied by the op-amp output.

Vs = 9.5 VRs = 10 kΩRL = 0.47 kΩ
IL = mA
2.Easy
−+Vout​Rf​ = 47 kΩVin​R1​ = ?

An inverting amplifier with an ideal op-amp must have a voltage gain of −10. The feedback resistor is Rf = 47 kΩ. Find the input resistor R1.

Av = −10Rf = 47 kΩ
R1 = kΩ
3.Medium
−+Vout​Rf​ = 47 kΩR1​ = 10 kΩVin​ = 2 VRa​ = 4.7 kΩRb​ = 22 kΩ

The op-amp is ideal and runs from ±15 V supplies. Find the output voltage Vout.

Vin = 2 VRa = 4.7 kΩRb = 22 kΩR1 = 10 kΩRf = 47 kΩ
Vout = V
4.Medium
−+Vout​R2​ = 4.7 kΩV1​ = 1.9 VR1​ = 22 kΩV2​ = 0.6 VR3​ = 22 kΩR4​ = 4.7 kΩ

The difference amplifier uses an ideal op-amp with ±15 V supplies, with R3 = R1 and R4 = R2. Find the output voltage Vout.

V1 = 1.9 VV2 = 0.6 VR1 = R3 = 22 kΩR2 = R4 = 4.7 kΩ
Vout = V
5.Hard
−+Vout​C = 2.2 µFVin​ = −2.8 VR = 100 kΩ

The integrator uses an ideal op-amp with ±15 V supplies; its output saturates at ±12 V. The capacitor is uncharged when a constant input Vin = −2.8 V is applied at t = 0. Find the output voltage Vout at t = 500 ms.

Vin = −2.8 VR = 100 kΩC = 2.2 µFVsat = ±12 Vt = 500 ms
Vout = V
6.Hard
−+Vout​Rf​ = 2 kΩV1​ = −1.9 VR1​ = 2 kΩV2​ = −1.3 VR2​ = 4.7 kΩ

The summing amplifier uses an ideal op-amp with ±15 V supplies. Find the output voltage Vout.

V1 = −1.9 VV2 = −1.3 VR1 = 2 kΩR2 = 4.7 kΩRf = 2 kΩ
Vout = V

Answer key

  1. 1. IL = 20.21 mA
  2. 2. R1 = 4.7 kΩ
  3. 3. Vout = 9.393 V
  4. 4. Vout = −0.2777 V
  5. 5. Vout = 6.364 V
  6. 6. Vout = 2.453 V

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