Op-amp circuits worksheet with answers

Free printable Op-amp circuits worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
−+Vout​1.5 VRs​ = 47 kΩRL​10 kΩ

A sensor behaves like a 1.5 V source with an internal resistance Rs = 47 kΩ. It feeds a load RL = 10 kΩ through an ideal voltage follower (unity-gain buffer). For comparison, find the load voltage VL if the load were connected directly to the sensor without the buffer.

Vs = 1.5 VRs = 47 kΩRL = 10 kΩ
VL = V
2.Easy
−+Vout​Rf​ = 22 kΩVin​ = 1.3 VR1​ = 10 kΩ

The op-amp is ideal and runs from ±15 V supplies. Find the output voltage Vout.

Vin = 1.3 VR1 = 10 kΩRf = 22 kΩ
Vout = V
3.Medium
−+Vout​Rf​ = ?R1​ = 1 kΩVin​

Choose the feedback resistor Rf that gives this non-inverting amplifier a voltage gain of 8.

R1 = 1 kΩAv = 8
Rf = kΩ
4.Medium
−+Vout​Rf​ = ?R1​ = 10 kΩVin​

Choose the feedback resistor Rf that gives this non-inverting amplifier a voltage gain of 20.

R1 = 10 kΩAv = 20
Rf = kΩ
5.Hard
−+Vout​Rf​ = 4.7 kΩV1​ = 0.8 VR1​ = 10 kΩV2​ = 0.1 VR2​ = 47 kΩ

The summing amplifier uses an ideal op-amp with ±15 V supplies. Find the output voltage Vout.

V1 = 0.8 VV2 = 0.1 VR1 = 10 kΩR2 = 47 kΩRf = 4.7 kΩ
Vout = V
6.Hard
−+Vout​C = 1 µFVin​ = 2 VR = 100 kΩ

The integrator uses an ideal op-amp with ±15 V supplies; its output saturates at ±14 V. The capacitor is uncharged when a constant input Vin = 2 V is applied at t = 0. Find the output voltage Vout at t = 500 ms.

Vin = 2 VR = 100 kΩC = 1 µFVsat = ±14 Vt = 500 ms
Vout = V

Answer key

  1. 1. VL = 0.2632 V
  2. 2. Vout = −2.86 V
  3. 3. Rf = 7 kΩ
  4. 4. Rf = 190 kΩ
  5. 5. Vout = −0.386 V
  6. 6. Vout = −10 V

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