Complete the truth table (1 = true, 0 = false). In how many rows N is (p ∨ q) ∧ (¬q ∨ ¬p) true?
Propositional logic & proofs worksheet with answers
1.Easy
(p ∨ q) ∧ (¬q ∨ ¬p)
N =
2.Easy
Exactly one row of the truth table makes ¬(q → r) ∨ ((p ∧ r) → q) false. Click that row.
¬(q → r) ∨ ((p ∧ r) → q)
- 1p = 1, q = 1, r = 1
- 2p = 1, q = 1, r = 0
- 3p = 1, q = 0, r = 1
- 4p = 1, q = 0, r = 0
- 5p = 0, q = 1, r = 1
- 6p = 0, q = 1, r = 0
- 7p = 0, q = 0, r = 1
- 8p = 0, q = 0, r = 0
3.Medium
In how many of the 8 rows of its truth table is ¬(r ∧ p) ∧ ((r → q) → p) true? Call this number N.
¬(r ∧ p) ∧ ((r → q) → p)
N =
4.Medium
Which formula is logically equivalent to (r ∨ p) → q? Click it.
(r ∨ p) → q
- 1(r → q) ∧ (p → q)
- 2(r → q) ∨ (p → q)
- 3r ∨ (p → q)
- 4(r ∧ p) → q
5.Hard
The argument with premises b → c; c and conclusion b is invalid. Click the row of the truth table that is a counterexample.
b → cc∴ b
- 1b = 1, c = 1
- 2b = 1, c = 0
- 3b = 0, c = 1
- 4b = 0, c = 0
6.Hard
Which statement is equivalent to ¬∃x ∀y R(x, y), with the negation moved all the way inside? Click it.
¬∃x ∀y R(x, y)
- 1∃x ∃y ¬R(x, y)
- 2∀x ∃y ¬R(x, y)
- 3∃x ∀y ¬R(x, y)
- 4∀x ∀y ¬R(x, y)
Answer key
- 1. N = 2
- 2. p = 1, q = 0, r = 1
- 3. N = 3
- 4. (r → q) ∧ (p → q)
- 5. b = 0, c = 1
- 6. ∀x ∃y ¬R(x, y)
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