Complete the truth table (1 = true, 0 = false). In how many rows N is ¬(¬r ∨ ¬q) ∨ (r → p) true?
Propositional logic & proofs worksheet with answers
1.Easy
¬(¬r ∨ ¬q) ∨ (r → p)
N =
2.Easy
Complete the truth table (1 = true, 0 = false). In how many rows N is p ∨ (q → p) true?
p ∨ (q → p)
N =
3.Medium
In how many of the 8 rows of its truth table is ¬(c ↔ b) → ((a → b) → (¬a ∧ c)) true? Call this number N.
¬(c ↔ b) → ((a → b) → (¬a ∧ c))
N =
4.Medium
You want to prove ¬q → (p ∧ r) by contrapositive. Which implication do you prove instead? Click it.
¬q → (p ∧ r)
- 1(p ∧ r) → ¬q
- 2¬(p ∧ r) → ¬¬q
- 3¬q ∧ ¬(p ∧ r)
- 4¬¬q → ¬(p ∧ r)
5.Hard
Which statement is equivalent to ¬∀x ∃y R(x, y), with the negation moved all the way inside? Click it.
¬∀x ∃y R(x, y)
- 1∃y ∀x ¬R(x, y)
- 2∀x ∃y ¬R(x, y)
- 3∀x ∀y ¬R(x, y)
- 4∃x ∀y ¬R(x, y)
6.Hard
The argument with premises r → q; p → q and conclusion r → p is invalid. Click the row of the truth table that is a counterexample.
r → qp → q∴ r → p
- 1p = 1, q = 1, r = 1
- 2p = 1, q = 1, r = 0
- 3p = 1, q = 0, r = 1
- 4p = 1, q = 0, r = 0
- 5p = 0, q = 1, r = 1
- 6p = 0, q = 1, r = 0
- 7p = 0, q = 0, r = 1
- 8p = 0, q = 0, r = 0
Answer key
- 1. N = 7
- 2. N = 3
- 3. N = 6
- 4. ¬(p ∧ r) → ¬¬q
- 5. ∃x ∀y ¬R(x, y)
- 6. p = 0, q = 1, r = 1
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