Reaction kinetics worksheet with answers

Free printable Reaction kinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
CA​ (mol/L)r0.1r = ?CB​ = 1 mol/L

The reaction A + B → C follows the rate law r = k·CA, with k = 0.05 s⁻¹. Find the reaction rate r when CA = 0.1 mol/L and CB = 1 mol/L.

r = k·CAk = 0.05 s⁻¹CA = 0.1 mol/LCB = 1 mol/L
r = mol/(L·s)
2.Easy
CA​ (mol/L)r0.4r = ?CB​ = 1 mol/L

The reaction A + B → C follows the rate law r = k·CA·CB, with k = 0.1 L/(mol·s). Find the reaction rate r when CA = 0.4 mol/L and CB = 1 mol/L.

r = k·CA·CBk = 0.1 L/(mol·s)CA = 0.4 mol/LCB = 1 mol/L
r = mol/(L·s)
3.Medium
t (min)C (mol/L)2 minC = ?

A reaction with rate law −rA = k·CA² has k = 0.8 L/(mol·min) and starts at 1 mol/L. Find the concentration CA after 2 min.

k = 0.8 L/(mol·min)CA0 = 1 mol/Lt = 2 min
CA = mol/L
4.Medium
t (min)C (mol/L)20 minC = ?

A reaction with rate law −rA = k·CA² has k = 0.05 L/(mol·min) and starts at 1 mol/L. Find the concentration CA after 20 min.

k = 0.05 L/(mol·min)CA0 = 1 mol/Lt = 20 min
CA = mol/L
5.Hard
Tk25 °C0.00565 °C?

A reaction has a rate constant of 0.005 min⁻¹ at 25 °C and an activation energy of 70 kJ/mol. Find the rate constant k2 at 65 °C.

k1 = 0.005 min⁻¹T1 = 25 °CT2 = 65 °CEa = 70 kJ/molR = 8.314 J/(mol·K)
k2 = min⁻¹
6.Hard
Tk30 °C0.0270 °C?

A reaction has a rate constant of 0.02 min⁻¹ at 30 °C and an activation energy of 60 kJ/mol. Find the rate constant k2 at 70 °C.

k1 = 0.02 min⁻¹T1 = 30 °CT2 = 70 °CEa = 60 kJ/molR = 8.314 J/(mol·K)
k2 = min⁻¹

Answer key

  1. 1. r = 0.005 mol/(L·s)
  2. 2. r = 0.04 mol/(L·s)
  3. 3. CA = 0.3846 mol/L
  4. 4. CA = 0.5 mol/L
  5. 5. k2 = 0.1412 min⁻¹
  6. 6. k2 = 0.3208 min⁻¹

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