Reaction kinetics worksheet with answers

Free printable Reaction kinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
CA​ (mol/L)r1r = ?CB​ = 0.1 mol/L

The reaction A + B → C follows the rate law r = k·CB, with k = 0.002 s⁻¹. Find the reaction rate r when CA = 1 mol/L and CB = 0.1 mol/L.

r = k·CBk = 0.002 s⁻¹CA = 1 mol/LCB = 0.1 mol/L
r = mol/(L·s)
2.Easy
CA​ (mol/L)r1.5r = ?CB​ = 0.3 mol/L

The reaction A + B → C follows the rate law r = k·CA, with k = 0.002 s⁻¹. Find the reaction rate r when CA = 1.5 mol/L and CB = 0.3 mol/L.

r = k·CAk = 0.002 s⁻¹CA = 1.5 mol/LCB = 0.3 mol/L
r = mol/(L·s)
3.Medium
t (min)X (%)t = ?75%

A second-order reaction (−rA = k·CA²) in a batch reactor has k = 0.2 L/(mol·min) and starts at 0.5 mol/L. How long does it take to reach 75% conversion? Find t.

k = 0.2 L/(mol·min)CA0 = 0.5 mol/LX = 75 %
t = min
4.Medium
t (min)X (%)t = ?90%

A first-order reaction in a batch reactor has k = 0.08 min⁻¹. How long does it take to reach 90% conversion? Find t.

k = 0.08 min⁻¹X = 90 %
t = min
5.Hard
Tk25 °C0.00265 °C0.0276

The rate constant of a reaction is 0.002 min⁻¹ at 25 °C and 0.0276 min⁻¹ at 65 °C. Find the activation energy Ea.

k1 = 0.002 min⁻¹T1 = 25 °Ck2 = 0.0276 min⁻¹T2 = 65 °CR = 8.314 J/(mol·K)
Ea = kJ/mol
6.Hard
Tk25 °C0.00565 °C0.0876

The rate constant of a reaction is 0.005 min⁻¹ at 25 °C and 0.0876 min⁻¹ at 65 °C. Find the activation energy Ea.

k1 = 0.005 min⁻¹T1 = 25 °Ck2 = 0.0876 min⁻¹T2 = 65 °CR = 8.314 J/(mol·K)
Ea = kJ/mol

Answer key

  1. 1. r = 0.0002 mol/(L·s)
  2. 2. r = 0.003 mol/(L·s)
  3. 3. t = 30 min
  4. 4. t = 28.78 min
  5. 5. Ea = 55 kJ/mol
  6. 6. Ea = 60 kJ/mol

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