Reaction kinetics worksheet with answers

Free printable Reaction kinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
t (min)C (mol/L)15 minC = ?

A first-order reaction A → products has a rate constant of 0.08 min⁻¹. The initial concentration of A is 1 mol/L. Find the concentration CA after 15 min.

k = 0.08 min⁻¹CA0 = 1 mol/Lt = 15 min
CA = mol/L
2.Easy
t (min)C (mol/L)10 minC = ?

A first-order reaction A → products has a rate constant of 0.2 min⁻¹. The initial concentration of A is 0.5 mol/L. Find the concentration CA after 10 min.

k = 0.2 min⁻¹CA0 = 0.5 mol/Lt = 10 min
CA = mol/L
3.Medium
t (min)C (mol/L)30 minC = ?

A reaction with rate law −rA = k·CA² has k = 0.1 L/(mol·min) and starts at 1 mol/L. Find the concentration CA after 30 min.

k = 0.1 L/(mol·min)CA0 = 1 mol/Lt = 30 min
CA = mol/L
4.Medium
t (min)C (mol/L)20 min0.525

In a first-order reaction the concentration of A falls from 1.5 mol/L to 0.525 mol/L in 20 min. Find the rate constant k.

CA0 = 1.5 mol/LCA = 0.525 mol/Lt = 20 min
k = min⁻¹
5.Hard
CA0​ (mol/L)r (mol/(L·s))run 10.50.01run 210.0283n = ?

Two experiments measure the initial rate of A → products. With CA0 = 0.5 mol/L the rate is 0.01 mol/(L·s); with CA0 = 1 mol/L it is 0.0283 mol/(L·s). Find the reaction order n with respect to A.

CA0,1 = 0.5 mol/Lr1 = 0.01 mol/(L·s)CA0,2 = 1 mol/Lr2 = 0.0283 mol/(L·s)
n =
6.Hard
Tk30 °C0.00240 °C?

A reaction has a rate constant of 0.002 min⁻¹ at 30 °C and an activation energy of 120 kJ/mol. Find the rate constant k2 at 40 °C.

k1 = 0.002 min⁻¹T1 = 30 °CT2 = 40 °CEa = 120 kJ/molR = 8.314 J/(mol·K)
k2 = min⁻¹

Answer key

  1. 1. CA = 0.3012 mol/L
  2. 2. CA = 0.06767 mol/L
  3. 3. CA = 0.25 mol/L
  4. 4. k = 0.05249 min⁻¹
  5. 5. n = 1.501
  6. 6. k2 = 0.009148 min⁻¹

Full step-by-step solutions: practise this topic on examproblems.com.