Reaction kinetics worksheet with answers

Free printable Reaction kinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
t (min)C (mol/L)30 minC = ?

A zero-order reaction A → products has a rate constant of 0.04 mol/(L·min). The initial concentration of A is 1.5 mol/L. Find the concentration CA after 30 min.

k = 0.04 mol/(L·min)CA0 = 1.5 mol/Lt = 30 min
CA = mol/L
2.Easy
t (min)C (mol/L)5 minC = ?

A first-order reaction A → products has a rate constant of 0.1 min⁻¹. The initial concentration of A is 1.5 mol/L. Find the concentration CA after 5 min.

k = 0.1 min⁻¹CA0 = 1.5 mol/Lt = 5 min
CA = mol/L
3.Medium
t (min)X (%)t = ?80%

A second-order reaction (−rA = k·CA²) in a batch reactor has k = 0.5 L/(mol·min) and starts at 1 mol/L. How long does it take to reach 80% conversion? Find t.

k = 0.5 L/(mol·min)CA0 = 1 mol/LX = 80 %
t = min
4.Medium
t (min)X (%)t = ?20%

A zero-order reaction has k = 0.04 mol/(L·min) and starts at 1.5 mol/L. How long does it take to reach 20% conversion? Find t.

k = 0.04 mol/(L·min)CA0 = 1.5 mol/LX = 20 %
t = min
5.Hard
t (min)X (%)60 minX = ?

A first-order reaction has k = 0.005 min⁻¹ at 20 °C and an activation energy of 80 kJ/mol. The batch reactor is now run at 40 °C for 60 min. Find the conversion X reached.

k1 = 0.005 min⁻¹T1 = 20 °CEa = 80 kJ/molT2 = 40 °Ct = 60 minR = 8.314 J/(mol·K)
X = %
6.Hard
Tk30 °C0.155 °C0.83

The rate constant of a reaction is 0.1 min⁻¹ at 30 °C and 0.83 min⁻¹ at 55 °C. Find the activation energy Ea.

k1 = 0.1 min⁻¹T1 = 30 °Ck2 = 0.83 min⁻¹T2 = 55 °CR = 8.314 J/(mol·K)
Ea = kJ/mol

Answer key

  1. 1. CA = 0.3 mol/L
  2. 2. CA = 0.9098 mol/L
  3. 3. t = 8 min
  4. 4. t = 7.5 min
  5. 5. X = 91.29 %
  6. 6. Ea = 70.01 kJ/mol

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