Reaction kinetics worksheet with answers

Free printable Reaction kinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
CA​ (mol/L)r0.8r = ?CB​ = 0.3 mol/L

The reaction A + B → C follows the rate law r = k·CA·CB, with k = 0.2 L/(mol·s). Find the reaction rate r when CA = 0.8 mol/L and CB = 0.3 mol/L.

r = k·CA·CBk = 0.2 L/(mol·s)CA = 0.8 mol/LCB = 0.3 mol/L
r = mol/(L·s)
2.Easy
t (min)C (mol/L)20 minC = ?

A first-order reaction A → products has a rate constant of 0.1 min⁻¹. The initial concentration of A is 0.5 mol/L. Find the concentration CA after 20 min.

k = 0.1 min⁻¹CA0 = 0.5 mol/Lt = 20 min
CA = mol/L
3.Medium
t (min)C (mol/L)t½​ = ?C0​/2

A second-order reaction (−rA = k·CA²) has k = 0.05 L/(mol·min) and an initial concentration of 1 mol/L. Find its first half-life t½.

k = 0.05 L/(mol·min)CA0 = 1 mol/L
t½ = min
4.Medium
t (min)C (mol/L)10 min0.2

In a first-order reaction the concentration of A falls from 1 mol/L to 0.2 mol/L in 10 min. Find the rate constant k.

CA0 = 1 mol/LCA = 0.2 mol/Lt = 10 min
k = min⁻¹
5.Hard
t (min)X (%)10 minX = ?

A first-order reaction has k = 0.02 min⁻¹ at 20 °C and an activation energy of 60 kJ/mol. The batch reactor is now run at 35 °C for 10 min. Find the conversion X reached.

k1 = 0.02 min⁻¹T1 = 20 °CEa = 60 kJ/molT2 = 35 °Ct = 10 minR = 8.314 J/(mol·K)
X = %
6.Hard
Tk20 °C0.00545 °C?

A reaction has a rate constant of 0.005 min⁻¹ at 20 °C and an activation energy of 75 kJ/mol. Find the rate constant k2 at 45 °C.

k1 = 0.005 min⁻¹T1 = 20 °CT2 = 45 °CEa = 75 kJ/molR = 8.314 J/(mol·K)
k2 = min⁻¹

Answer key

  1. 1. r = 0.048 mol/(L·s)
  2. 2. CA = 0.06767 mol/L
  3. 3. t½ = 20 min
  4. 4. k = 0.1609 min⁻¹
  5. 5. X = 48.47 %
  6. 6. k2 = 0.05612 min⁻¹

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