Reaction kinetics worksheet with answers

Free printable Reaction kinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
CA​ (mol/L)r2r = ?CB​ = 1 mol/L

The reaction A + B → C follows the rate law r = k·CB², with k = 0.005 L/(mol·s). Find the reaction rate r when CA = 2 mol/L and CB = 1 mol/L.

r = k·CB²k = 0.005 L/(mol·s)CA = 2 mol/LCB = 1 mol/L
r = mol/(L·s)
2.Easy
t (min)C (mol/L)40 minC = ?

A first-order reaction A → products has a rate constant of 0.02 min⁻¹. The initial concentration of A is 1.2 mol/L. Find the concentration CA after 40 min.

k = 0.02 min⁻¹CA0 = 1.2 mol/Lt = 40 min
CA = mol/L
3.Medium
t (min)X (%)t = ?90%

A second-order reaction (−rA = k·CA²) in a batch reactor has k = 0.5 L/(mol·min) and starts at 0.5 mol/L. How long does it take to reach 90% conversion? Find t.

k = 0.5 L/(mol·min)CA0 = 0.5 mol/LX = 90 %
t = min
4.Medium
t (min)X (%)t = ?80%

A second-order reaction (−rA = k·CA²) in a batch reactor has k = 0.05 L/(mol·min) and starts at 0.5 mol/L. How long does it take to reach 80% conversion? Find t.

k = 0.05 L/(mol·min)CA0 = 0.5 mol/LX = 80 %
t = min
5.Hard
Tk40 °C0.00260 °C?

A reaction has a rate constant of 0.002 min⁻¹ at 40 °C and an activation energy of 70 kJ/mol. Find the rate constant k2 at 60 °C.

k1 = 0.002 min⁻¹T1 = 40 °CT2 = 60 °CEa = 70 kJ/molR = 8.314 J/(mol·K)
k2 = min⁻¹
6.Hard
Tk20 °C0.130 °C0.338

The rate constant of a reaction is 0.1 min⁻¹ at 20 °C and 0.338 min⁻¹ at 30 °C. Find the activation energy Ea.

k1 = 0.1 min⁻¹T1 = 20 °Ck2 = 0.338 min⁻¹T2 = 30 °CR = 8.314 J/(mol·K)
Ea = kJ/mol

Answer key

  1. 1. r = 0.005 mol/(L·s)
  2. 2. CA = 0.5392 mol/L
  3. 3. t = 36 min
  4. 4. t = 160 min
  5. 5. k2 = 0.01005 min⁻¹
  6. 6. Ea = 89.98 kJ/mol

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