Rigid-body rotation worksheet with answers

Free printable Rigid-body rotation worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
k = 0.35 m100 → 300 rpm100 kg

A flywheel of mass 100 kg with a radius of gyration of 0.35 m is accelerated uniformly from 100 rpm to 300 rpm. This takes 8 s. Ignoring friction, find the constant torque T needed.

m = 100 kgk = 0.35 mn1 = 100 rpmn2 = 300 rpmt = 8 s
T = N·m
2.Easy
k = 0.35 m0 → 1400 rpm140 kg

A flywheel of mass 140 kg with a radius of gyration of 0.35 m is accelerated uniformly from rest to 1400 rpm. This takes 25 s. Ignoring friction, find the constant torque T needed.

m = 140 kgk = 0.35 mn1 = 0 rpmn2 = 1400 rpmt = 25 s
T = N·m
3.Medium
L = 1.2 mm = 5.5 kgα

A uniform slender rod of mass 5.5 kg and length 1.2 m is pinned at one end and held horizontal. It is released from rest. Use g = 9.81 m/s². Find the vertical force R that the pin exerts on the rod just after release.

m = 5.5 kgL = 1.2 mg = 9.81 m/s²
R = N
4.Medium
2 kgaαM = 9 kgR = 0.3 m

A 2 kg block hangs from a light cord wrapped around a pulley, a uniform solid disc of mass 9 kg and radius 0.3 m that turns on a frictionless horizontal axle. The block is released from rest. Use g = 9.81 m/s². Find the acceleration a of the block.

m = 2 kgM = 9 kgR = 0.3 mg = 9.81 m/s²
a = m/s²
5.Hard
8 m/sω

A solid cylinder of mass 2 kg rolls without slipping at 8 m/s. What percentage p of its total kinetic energy is rotational?

m = 2 kgv = 8 m/sI = ½·m·r²
p = %
6.Hard
5 m/sω

A solid cylinder of mass 13 kg rolls without slipping at 5 m/s. Find its rotational kinetic energy Erot.

m = 13 kgv = 5 m/sI = ½·m·r²
Erot = J

Answer key

  1. 1. T = 32.07 N·m
  2. 2. T = 100.6 N·m
  3. 3. R = 13.49 N
  4. 4. a = 3.018 m/s²
  5. 5. p = 33.33 %
  6. 6. Erot = 81.25 J

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