Rigid-body rotation worksheet with answers

Free printable Rigid-body rotation worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
k = 0.15 m600 → 1400 rpm140 kg

A flywheel of mass 140 kg with a radius of gyration of 0.15 m is accelerated uniformly from 600 rpm to 1400 rpm. This takes 20 s. Ignoring friction, find the constant torque T needed.

m = 140 kgk = 0.15 mn1 = 600 rpmn2 = 1400 rpmt = 20 s
T = N·m
2.Easy
Or = 0.2 mL = 1.4 m1.6 m4.5 kg6 kg

A pendulum is made of a uniform slender rod (4.5 kg, 1.4 m long) pivoted at its top end O, with a solid sphere of mass 6 kg and radius 0.2 m fixed to its lower end. The centre of the sphere is 1.6 m below O. Find the mass moment of inertia IO of the pendulum about O.

mrod = 4.5 kgL = 1.4 mmsphere = 6 kgr = 0.2 md = 1.6 m
IO = kg·m²
3.Medium
n = 1500 rpmTb​ = 60 N·mI = 19 kg·m²

A flywheel with a moment of inertia of 19 kg·m² spins at 1500 rpm. A brake applies a constant friction torque of 60 N·m. How long t does it take to stop?

I = 19 kg·m²n = 1500 rpmTb = 60 N·m
t = s
4.Medium
3 kgaαM = 19.5 kgR = 0.5 m

A 3 kg block hangs from a light cord wrapped around a pulley, a uniform solid disc of mass 19.5 kg and radius 0.5 m that turns on a frictionless horizontal axle. The block is released from rest. Use g = 9.81 m/s². Find the speed v of the block after it has fallen 3 m.

m = 3 kgM = 19.5 kgR = 0.5 mg = 9.81 m/s²h = 3 m
v = m/s
5.Hard
460 m/s40 g0.35 mL = 0.5 m1 kg

A uniform slender rod of mass 1 kg and length 0.5 m hangs at rest from a frictionless pivot at its top end. A 40 g bullet moving horizontally at 460 m/s hits the rod 0.35 m below the pivot and stays embedded. Find the angular velocity ω of the rod just after the impact.

M = 1 kgL = 0.5 mm = 40 gv = 460 m/sd = 0.35 m
ω = rad/s
6.Hard
140 m/s35 g1.13 mL = 1.7 m8 kgφ

A uniform slender rod of mass 8 kg and length 1.7 m hangs at rest from a frictionless pivot at its top end. A 35 g bullet moving horizontally at 140 m/s hits the rod 1.13 m below the pivot and stays embedded. Use g = 9.81 m/s². Find the largest angle φ from the vertical through which the rod swings.

M = 8 kgL = 1.7 mm = 35 gv = 140 m/sd = 1.13 mg = 9.81 m/s²
φ = °

Answer key

  1. 1. T = 13.19 N·m
  2. 2. IO = 18.4 kg·m²
  3. 3. t = 49.74 s
  4. 4. v = 3.721 m/s
  5. 5. ω = 72.99 rad/s
  6. 6. φ = 13.95 °

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