Rigid-body rotation worksheet with answers

Free printable Rigid-body rotation worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
k = 0.35 m900 → 1400 rpm30 kg

A flywheel of mass 30 kg with a radius of gyration of 0.35 m is accelerated uniformly from 900 rpm to 1400 rpm. The driving torque is a constant 96 N·m and friction can be ignored. How long t does this take?

m = 30 kgk = 0.35 mn1 = 900 rpmn2 = 1400 rpmT = 96 N·m
t = s
2.Easy
k = 0.15 m800 → 1700 rpm170 kg

A flywheel of mass 170 kg with a radius of gyration of 0.15 m is accelerated uniformly from 800 rpm to 1700 rpm. This takes 22 s. Ignoring friction, find the constant torque T needed.

m = 170 kgk = 0.15 mn1 = 800 rpmn2 = 1700 rpmt = 22 s
T = N·m
3.Medium
v = ?L = 1.8 mm = 3 kg

A uniform slender rod of mass 3 kg and length 1.8 m is pinned at one end and released from rest in a horizontal position. Ignore friction and use g = 9.81 m/s². Find the speed v of the free end as the rod swings through the vertical position.

m = 3 kgL = 1.8 mg = 9.81 m/s²
v = m/s
4.Medium
0 → 1000 rpmI = 13 kg·m²

A motor brings a flywheel with a moment of inertia of 13 kg·m² from rest up to 1000 rpm in 11 s. Ignoring losses, find the average power Pavg it delivers, in kW.

I = 13 kg·m²n = 1000 rpmt = 11 s
Pavg = kW
5.Hard
3 m/sω

A solid cylinder of mass 2 kg rolls without slipping at 3 m/s. Find its rotational kinetic energy Erot.

m = 2 kgv = 3 m/sI = ½·m·r²
Erot = J
6.Hard
1 m/sω

A solid sphere of mass 18.5 kg rolls without slipping at 1 m/s. Find its total kinetic energy Ek.

m = 18.5 kgv = 1 m/sI = (2/5)·m·r²
Ek = J

Answer key

  1. 1. t = 2.004 s
  2. 2. T = 16.39 N·m
  3. 3. v = 7.278 m/s
  4. 4. Pavg = 6.48 kW
  5. 5. Erot = 4.5 J
  6. 6. Ek = 12.95 J

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