Rigid-body rotation worksheet with answers

Free printable Rigid-body rotation worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Or = 0.25 mL = 1.5 m1.75 m2.5 kg6 kg

A pendulum is made of a uniform slender rod (2.5 kg, 1.5 m long) pivoted at its top end O, with a thin solid disc of mass 6 kg and radius 0.25 m fixed to its lower end. The disc swings in its own plane and its centre is 1.75 m below O. Find the mass moment of inertia IO of the pendulum about O.

mrod = 2.5 kgL = 1.5 mmdisc = 6 kgr = 0.25 md = 1.75 m
IO = kg·m²
2.Easy
k = 0.35 m0 → 1700 rpm10 kg

A flywheel of mass 10 kg with a radius of gyration of 0.35 m is accelerated uniformly from rest to 1700 rpm. The driving torque is a constant 15 N·m and friction can be ignored. How long t does this take?

m = 10 kgk = 0.35 mn1 = 0 rpmn2 = 1700 rpmT = 15 N·m
t = s
3.Medium
L = 2.6 mm = 9.5 kgα

A uniform slender rod of mass 9.5 kg and length 2.6 m is pinned at one end and held horizontal. It is released from rest. Use g = 9.81 m/s². Find the acceleration atip of the free end just after release.

m = 9.5 kgL = 2.6 mg = 9.81 m/s²
atip = m/s²
4.Medium
6 kgaαM = 7.5 kgR = 0.45 m

A 6 kg block hangs from a light cord wrapped around a pulley, a uniform solid disc of mass 7.5 kg and radius 0.45 m that turns on a frictionless horizontal axle. The block is released from rest. Use g = 9.81 m/s². Find the angular acceleration α of the pulley.

m = 6 kgM = 7.5 kgR = 0.45 mg = 9.81 m/s²
α = rad/s²
5.Hard
disc: 40 kgring: 16 kgn1​ = 450 rpm

A uniform solid disc (mass 40 kg, radius 0.2 m) spins freely at 450 rpm about a vertical frictionless shaft. A thin ring of mass 16 kg and the same radius is dropped onto it from rest, centred on the shaft, and the two quickly spin together. How much kinetic energy ΔE is lost in the process?

Mdisc = 40 kgMring = 16 kgR = 0.2 mn1 = 450 rpm
ΔE = J
6.Hard
6 m/sω

A solid sphere of mass 2 kg rolls without slipping at 6 m/s. Find its rotational kinetic energy Erot.

m = 2 kgv = 6 m/sI = (2/5)·m·r²
Erot = J

Answer key

  1. 1. IO = 20.44 kg·m²
  2. 2. t = 14.54 s
  3. 3. atip = 14.71 m/s²
  4. 4. α = 13.42 rad/s²
  5. 5. ΔE = 394.8 J
  6. 6. Erot = 14.4 J

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