Rigid-body rotation worksheet with answers

Free printable Rigid-body rotation worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
k = 0.5 m600 → 2300 rpm190 kg

A flywheel of mass 190 kg with a radius of gyration of 0.5 m is accelerated uniformly from 600 rpm to 2300 rpm. This takes 15 s. Ignoring friction, find the constant torque T needed.

m = 190 kgk = 0.5 mn1 = 600 rpmn2 = 2300 rpmt = 15 s
T = N·m
2.Easy
Or = 0.2 mL = 1.4 m1.6 m2.5 kg9 kg

A pendulum is made of a uniform slender rod (2.5 kg, 1.4 m long) pivoted at its top end O, with a thin solid disc of mass 9 kg and radius 0.2 m fixed to its lower end. The disc swings in its own plane and its centre is 1.6 m below O. Find the mass moment of inertia IO of the pendulum about O.

mrod = 2.5 kgL = 1.4 mmdisc = 9 kgr = 0.2 md = 1.6 m
IO = kg·m²
3.Medium
n = 2300 rpmTb​ = 140 N·mI = 7 kg·m²

A flywheel with a moment of inertia of 7 kg·m² spins at 2300 rpm. A brake applies a constant friction torque of 140 N·m. How long t does it take to stop?

I = 7 kg·m²n = 2300 rpmTb = 140 N·m
t = s
4.Medium
n = 2400 rpmTb​ = 170 N·mI = 12 kg·m²

A flywheel with a moment of inertia of 12 kg·m² spins at 2400 rpm. A brake applies a constant friction torque of 170 N·m. How long t does it take to stop?

I = 12 kg·m²n = 2400 rpmTb = 170 N·m
t = s
5.Hard
2 m/sω

A solid cylinder of mass 10.5 kg rolls without slipping at 2 m/s. What percentage p of its total kinetic energy is rotational?

m = 10.5 kgv = 2 m/sI = ½·m·r²
p = %
6.Hard
6 m/sω

A solid sphere of mass 13 kg rolls without slipping at 6 m/s. What percentage p of its total kinetic energy is rotational?

m = 13 kgv = 6 m/sI = (2/5)·m·r²
p = %

Answer key

  1. 1. T = 563.7 N·m
  2. 2. IO = 24.85 kg·m²
  3. 3. t = 12.04 s
  4. 4. t = 17.74 s
  5. 5. p = 33.33 %
  6. 6. p = 28.57 %

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