Rigid-body rotation worksheet with answers

Free printable Rigid-body rotation worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
k = 0.55 m1000 → 1700 rpm20 kg

A flywheel of mass 20 kg with a radius of gyration of 0.55 m is accelerated uniformly from 1000 rpm to 1700 rpm. This takes 25 s. Ignoring friction, find the constant torque T needed.

m = 20 kgk = 0.55 mn1 = 1000 rpmn2 = 1700 rpmt = 25 s
T = N·m
2.Easy
Or = 0.1 mL = 1.5 m1.6 m5 kg4 kg

A pendulum is made of a uniform slender rod (5 kg, 1.5 m long) pivoted at its top end O, with a thin solid disc of mass 4 kg and radius 0.1 m fixed to its lower end. The disc swings in its own plane and its centre is 1.6 m below O. Find the mass moment of inertia IO of the pendulum about O.

mrod = 5 kgL = 1.5 mmdisc = 4 kgr = 0.1 md = 1.6 m
IO = kg·m²
3.Medium
n = 1700 rpmTb​ = 140 N·mI = 7 kg·m²

A flywheel with a moment of inertia of 7 kg·m² spins at 1700 rpm. A brake applies a constant friction torque of 140 N·m. How long t does it take to stop?

I = 7 kg·m²n = 1700 rpmTb = 140 N·m
t = s
4.Medium
L = 2.9 mm = 9 kgα

A uniform slender rod of mass 9 kg and length 2.9 m is pinned at one end and held horizontal. It is released from rest. Use g = 9.81 m/s². Find the vertical force R that the pin exerts on the rod just after release.

m = 9 kgL = 2.9 mg = 9.81 m/s²
R = N
5.Hard
θ = 30°as = 6 m

A solid sphere rolls without slipping down a slope inclined at 30° to the horizontal. Use g = 9.81 m/s². It starts from rest. How long t does it take to roll 6 m down the slope?

θ = 30°I = (2/5)·m·r²g = 9.81 m/s²s = 6 m
t = s
6.Hard
6 m/sω

A hollow sphere of mass 18 kg rolls without slipping at 6 m/s. Find its rotational kinetic energy Erot.

m = 18 kgv = 6 m/sI = (2/3)·m·r²
Erot = J

Answer key

  1. 1. T = 17.74 N·m
  2. 2. IO = 14.01 kg·m²
  3. 3. t = 8.901 s
  4. 4. R = 22.07 N
  5. 5. t = 1.851 s
  6. 6. Erot = 216 J

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