Rigid-body rotation worksheet with answers

Free printable Rigid-body rotation worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Or = 0.15 mL = 0.8 m0.95 m4.5 kg7.5 kg

A pendulum is made of a uniform slender rod (4.5 kg, 0.8 m long) pivoted at its top end O, with a solid sphere of mass 7.5 kg and radius 0.15 m fixed to its lower end. The centre of the sphere is 0.95 m below O. Find the mass moment of inertia IO of the pendulum about O.

mrod = 4.5 kgL = 0.8 mmsphere = 7.5 kgr = 0.15 md = 0.95 m
IO = kg·m²
2.Easy
k = 0.55 m500 → 1400 rpm160 kg

A flywheel of mass 160 kg with a radius of gyration of 0.55 m is accelerated uniformly from 500 rpm to 1400 rpm. This takes 18 s. Ignoring friction, find the constant torque T needed.

m = 160 kgk = 0.55 mn1 = 500 rpmn2 = 1400 rpmt = 18 s
T = N·m
3.Medium
ω = ?L = 2.1 mm = 3.5 kg

A uniform slender rod of mass 3.5 kg and length 2.1 m is pinned at one end and released from rest in a horizontal position. Ignore friction and use g = 9.81 m/s². Find the angular velocity ω of the rod as it swings through the vertical position.

m = 3.5 kgL = 2.1 mg = 9.81 m/s²
ω = rad/s
4.Medium
L = 1.5 mm = 6.5 kgα

A uniform slender rod of mass 6.5 kg and length 1.5 m is pinned at one end and held horizontal. It is released from rest. Use g = 9.81 m/s². Find the acceleration atip of the free end just after release.

m = 6.5 kgL = 1.5 mg = 9.81 m/s²
atip = m/s²
5.Hard
1.5 m/sω

A hollow sphere of mass 7.5 kg rolls without slipping at 1.5 m/s. What percentage p of its total kinetic energy is rotational?

m = 7.5 kgv = 1.5 m/sI = (2/3)·m·r²
p = %
6.Hard
3.5 m/sω

A solid sphere of mass 16.5 kg rolls without slipping at 3.5 m/s. What percentage p of its total kinetic energy is rotational?

m = 16.5 kgv = 3.5 m/sI = (2/5)·m·r²
p = %

Answer key

  1. 1. IO = 7.796 kg·m²
  2. 2. T = 253.4 N·m
  3. 3. ω = 3.744 rad/s
  4. 4. atip = 14.71 m/s²
  5. 5. p = 40 %
  6. 6. p = 28.57 %

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