Rigid-body rotation worksheet with answers

Free printable Rigid-body rotation worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
k = 0.25 m0 → 800 rpm150 kg

A flywheel of mass 150 kg with a radius of gyration of 0.25 m is accelerated uniformly from rest to 800 rpm. The driving torque is a constant 52 N·m and friction can be ignored. How long t does this take?

m = 150 kgk = 0.25 mn1 = 0 rpmn2 = 800 rpmT = 52 N·m
t = s
2.Easy
Or = 0.05 mL = 1.1 m1.15 m4 kg9 kg

A pendulum is made of a uniform slender rod (4 kg, 1.1 m long) pivoted at its top end O, with a solid sphere of mass 9 kg and radius 0.05 m fixed to its lower end. The centre of the sphere is 1.15 m below O. Find the mass moment of inertia IO of the pendulum about O.

mrod = 4 kgL = 1.1 mmsphere = 9 kgr = 0.05 md = 1.15 m
IO = kg·m²
3.Medium
0 → 3000 rpmI = 27 kg·m²

A motor brings a flywheel with a moment of inertia of 27 kg·m² from rest up to 3000 rpm in 15 s. Ignoring losses, find the average power Pavg it delivers, in kW.

I = 27 kg·m²n = 3000 rpmt = 15 s
Pavg = kW
4.Medium
L = 2.4 mm = 13.5 kgα

A uniform slender rod of mass 13.5 kg and length 2.4 m is pinned at one end and held horizontal. It is released from rest. Use g = 9.81 m/s². Find the acceleration atip of the free end just after release.

m = 13.5 kgL = 2.4 mg = 9.81 m/s²
atip = m/s²
5.Hard
θ = 25°vs = 2.5 m

A thin hoop starts from rest and rolls without slipping down a slope inclined at 25° to the horizontal. Use g = 9.81 m/s². Its radius is 0.05 m. Find its angular velocity ω after it has rolled 2.5 m along the slope.

θ = 25°s = 2.5 mI = m·r²g = 9.81 m/s²r = 0.05 m
ω = rad/s
6.Hard
θ = 15°a

A solid sphere rolls without slipping down a slope inclined at 15° to the horizontal. Use g = 9.81 m/s². Find the acceleration a of its centre.

θ = 15°I = (2/5)·m·r²g = 9.81 m/s²
a = m/s²

Answer key

  1. 1. t = 15.1 s
  2. 2. IO = 13.52 kg·m²
  3. 3. Pavg = 88.83 kW
  4. 4. atip = 14.71 m/s²
  5. 5. ω = 64.39 rad/s
  6. 6. a = 1.814 m/s²

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