Rigid-body rotation worksheet with answers

Free printable Rigid-body rotation worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
k = 0.3 m0 → 900 rpm140 kg

A flywheel of mass 140 kg with a radius of gyration of 0.3 m is accelerated uniformly from rest to 900 rpm. The driving torque is a constant 79 N·m and friction can be ignored. How long t does this take?

m = 140 kgk = 0.3 mn1 = 0 rpmn2 = 900 rpmT = 79 N·m
t = s
2.Easy
Or = 0.1 mL = 1.5 m1.6 m4 kg2 kg

A pendulum is made of a uniform slender rod (4 kg, 1.5 m long) pivoted at its top end O, with a solid sphere of mass 2 kg and radius 0.1 m fixed to its lower end. The centre of the sphere is 1.6 m below O. Find the mass moment of inertia IO of the pendulum about O.

mrod = 4 kgL = 1.5 mmsphere = 2 kgr = 0.1 md = 1.6 m
IO = kg·m²
3.Medium
L = 1.7 mm = 13.5 kgα

A uniform slender rod of mass 13.5 kg and length 1.7 m is pinned at one end and held horizontal. It is released from rest. Use g = 9.81 m/s². Find the acceleration atip of the free end just after release.

m = 13.5 kgL = 1.7 mg = 9.81 m/s²
atip = m/s²
4.Medium
L = 2.2 mm = 3 kgα

A uniform slender rod of mass 3 kg and length 2.2 m is pinned at one end and held horizontal. It is released from rest. Use g = 9.81 m/s². Find the vertical force R that the pin exerts on the rod just after release.

m = 3 kgL = 2.2 mg = 9.81 m/s²
R = N
5.Hard
θ = 25°a

A solid sphere rolls without slipping down a slope inclined at 25° to the horizontal. Use g = 9.81 m/s². Find the smallest coefficient of static friction μs that prevents it from slipping.

θ = 25°I = (2/5)·m·r²g = 9.81 m/s²
μs =
6.Hard
θ = 40°vs = 8 m

A solid sphere starts from rest and rolls without slipping down a slope inclined at 40° to the horizontal. Use g = 9.81 m/s². Find its speed v after it has rolled 8 m along the slope.

θ = 40°s = 8 mI = (2/5)·m·r²g = 9.81 m/s²
v = m/s

Answer key

  1. 1. t = 15.03 s
  2. 2. IO = 8.128 kg·m²
  3. 3. atip = 14.71 m/s²
  4. 4. R = 7.358 N
  5. 5. μs = 0.1332
  6. 6. v = 8.489 m/s

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