Rigid-body rotation worksheet with answers

Free printable Rigid-body rotation worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
k = 0.2 m0 → 1800 rpm100 kg

A flywheel of mass 100 kg with a radius of gyration of 0.2 m is accelerated uniformly from rest to 1800 rpm. The driving torque is a constant 31 N·m and friction can be ignored. How long t does this take?

m = 100 kgk = 0.2 mn1 = 0 rpmn2 = 1800 rpmT = 31 N·m
t = s
2.Easy
k = 0.55 mn = 800 rpm100 kg

A flywheel of mass 100 kg has a radius of gyration of 0.55 m about its axis. It spins at 800 rpm. Find its kinetic energy Ek in kJ.

M = 100 kgk = 0.55 mn = 800 rpm
Ek = kJ
3.Medium
L = 0.9 mm = 19.5 kgα

A uniform slender rod of mass 19.5 kg and length 0.9 m is pinned at one end and held horizontal. It is released from rest. Use g = 9.81 m/s². Find the vertical force R that the pin exerts on the rod just after release.

m = 19.5 kgL = 0.9 mg = 9.81 m/s²
R = N
4.Medium
ω = ?4.5 kgL = 1.9 mm = 4.5 kg

A uniform slender rod of mass 4.5 kg and length 1.9 m is pinned at one end and released from rest in a horizontal position. A small ball of mass 4.5 kg is fixed to its free end. Ignore friction and use g = 9.81 m/s². Find the angular velocity ω of the rod as it swings through the vertical position.

m = 4.5 kgL = 1.9 mmball = 4.5 kgg = 9.81 m/s²
ω = rad/s
5.Hard
320 m/s25 g0.47 mL = 0.8 m7.5 kgφ

A uniform slender rod of mass 7.5 kg and length 0.8 m hangs at rest from a frictionless pivot at its top end. A 25 g bullet moving horizontally at 320 m/s hits the rod 0.47 m below the pivot and stays embedded. Use g = 9.81 m/s². Find the largest angle φ from the vertical through which the rod swings.

M = 7.5 kgL = 0.8 mm = 25 gv = 320 m/sd = 0.47 mg = 9.81 m/s²
φ = °
6.Hard
disc: 30 kgring: 9 kgn1​ = 900 rpm

A uniform solid disc (mass 30 kg, radius 0.1 m) spins freely at 900 rpm about a vertical frictionless shaft. A thin ring of mass 9 kg and the same radius is dropped onto it from rest, centred on the shaft, and the two quickly spin together. Find their common speed n2 in rpm.

Mdisc = 30 kgMring = 9 kgR = 0.1 mn1 = 900 rpm
n2 = rpm

Answer key

  1. 1. t = 24.32 s
  2. 2. Ek = 106.2 kJ
  3. 3. R = 47.82 N
  4. 4. ω = 3.408 rad/s
  5. 5. φ = 31.68 °
  6. 6. n2 = 562.5 rpm

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