Rigid-body rotation worksheet with answers

Free printable Rigid-body rotation worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Or = 0.25 mL = 0.6 m0.85 m2 kg10 kg

A pendulum is made of a uniform slender rod (2 kg, 0.6 m long) pivoted at its top end O, with a solid sphere of mass 10 kg and radius 0.25 m fixed to its lower end. The centre of the sphere is 0.85 m below O. Find the mass moment of inertia IO of the pendulum about O.

mrod = 2 kgL = 0.6 mmsphere = 10 kgr = 0.25 md = 0.85 m
IO = kg·m²
2.Easy
k = 0.55 mn = 2500 rpm90 kg

A flywheel of mass 90 kg has a radius of gyration of 0.55 m about its axis. It spins at 2500 rpm. Find its kinetic energy Ek in kJ.

M = 90 kgk = 0.55 mn = 2500 rpm
Ek = kJ
3.Medium
v = ?L = 0.7 mm = 8 kg

A uniform slender rod of mass 8 kg and length 0.7 m is pinned at one end and released from rest in a horizontal position. Ignore friction and use g = 9.81 m/s². Find the speed v of the free end as the rod swings through the vertical position.

m = 8 kgL = 0.7 mg = 9.81 m/s²
v = m/s
4.Medium
0 → 1700 rpmI = 30 kg·m²

A motor brings a flywheel with a moment of inertia of 30 kg·m² from rest up to 1700 rpm in 42 s. Ignoring losses, find the average power Pavg it delivers, in kW.

I = 30 kg·m²n = 1700 rpmt = 42 s
Pavg = kW
5.Hard
2.5 m/sω

A solid sphere of mass 2.5 kg rolls without slipping at 2.5 m/s. Find its rotational kinetic energy Erot.

m = 2.5 kgv = 2.5 m/sI = (2/5)·m·r²
Erot = J
6.Hard
θ = 15°vs = 9.5 m

A solid sphere starts from rest and rolls without slipping down a slope inclined at 15° to the horizontal. Use g = 9.81 m/s². Find its speed v after it has rolled 9.5 m along the slope.

θ = 15°s = 9.5 mI = (2/5)·m·r²g = 9.81 m/s²
v = m/s

Answer key

  1. 1. IO = 7.715 kg·m²
  2. 2. Ek = 933 kJ
  3. 3. v = 4.539 m/s
  4. 4. Pavg = 11.32 kW
  5. 5. Erot = 3.125 J
  6. 6. v = 5.87 m/s

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