Rigid-body rotation worksheet with answers

Free printable Rigid-body rotation worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Or = 0.05 mL = 1 m1.05 m0.5 kg10 kg

A pendulum is made of a uniform slender rod (0.5 kg, 1 m long) pivoted at its top end O, with a solid sphere of mass 10 kg and radius 0.05 m fixed to its lower end. The centre of the sphere is 1.05 m below O. Find the mass moment of inertia IO of the pendulum about O.

mrod = 0.5 kgL = 1 mmsphere = 10 kgr = 0.05 md = 1.05 m
IO = kg·m²
2.Easy
k = 0.2 m0 → 1700 rpm130 kg

A flywheel of mass 130 kg with a radius of gyration of 0.2 m is accelerated uniformly from rest to 1700 rpm. This takes 28 s. Ignoring friction, find the constant torque T needed.

m = 130 kgk = 0.2 mn1 = 0 rpmn2 = 1700 rpmt = 28 s
T = N·m
3.Medium
8 kgaαM = 19.5 kgR = 0.5 m

An 8 kg block hangs from a light cord wrapped around a pulley, a uniform solid disc of mass 19.5 kg and radius 0.5 m that turns on a frictionless horizontal axle. The block is released from rest. Use g = 9.81 m/s². Find the angular acceleration α of the pulley.

m = 8 kgM = 19.5 kgR = 0.5 mg = 9.81 m/s²
α = rad/s²
4.Medium
n = 3000 rpmTb​ = 80 N·mI = 1.5 kg·m²

A flywheel with a moment of inertia of 1.5 kg·m² spins at 3000 rpm. A brake applies a constant friction torque of 80 N·m. How long t does it take to stop?

I = 1.5 kg·m²n = 3000 rpmTb = 80 N·m
t = s
5.Hard
0.7 m0.35 mn1​ = 60 rpm

A person stands on a frictionless turntable and holds a 4 kg dumbbell in each hand, 0.7 m from the axis. The person and turntable alone have a moment of inertia of 1.5 kg·m² about the axis. They turn at 60 rpm, then pull the dumbbells in to 0.35 m from the axis. Treat the dumbbells as point masses. Find the new speed n2 in rpm.

I0 = 1.5 kg·m²m = 2 × 4 kgr1 = 0.7 mr2 = 0.35 mn1 = 60 rpm
n2 = rpm
6.Hard
220 m/s40 g0.38 mL = 0.7 m7.5 kg

A uniform slender rod of mass 7.5 kg and length 0.7 m hangs at rest from a frictionless pivot at its top end. A 40 g bullet moving horizontally at 220 m/s hits the rod 0.38 m below the pivot and stays embedded. Find the angular velocity ω of the rod just after the impact.

M = 7.5 kgL = 0.7 mm = 40 gv = 220 m/sd = 0.38 m
ω = rad/s

Answer key

  1. 1. IO = 11.2 kg·m²
  2. 2. T = 33.06 N·m
  3. 3. α = 8.843 rad/s²
  4. 4. t = 5.89 s
  5. 5. n2 = 131.1 rpm
  6. 6. ω = 2.717 rad/s

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