Rigid-body rotation worksheet with answers

Free printable Rigid-body rotation worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Or = 0.1 mL = 0.9 m1 m0.5 kg2.5 kg

A pendulum is made of a uniform slender rod (0.5 kg, 0.9 m long) pivoted at its top end O, with a thin solid disc of mass 2.5 kg and radius 0.1 m fixed to its lower end. The disc swings in its own plane and its centre is 1 m below O. Find the mass moment of inertia IO of the pendulum about O.

mrod = 0.5 kgL = 0.9 mmdisc = 2.5 kgr = 0.1 md = 1 m
IO = kg·m²
2.Easy
k = 0.6 m500 → 1200 rpm120 kg

A flywheel of mass 120 kg with a radius of gyration of 0.6 m is accelerated uniformly from 500 rpm to 1200 rpm. The driving torque is a constant 450 N·m and friction can be ignored. How long t does this take?

m = 120 kgk = 0.6 mn1 = 500 rpmn2 = 1200 rpmT = 450 N·m
t = s
3.Medium
n = 900 rpmTb​ = 50 N·mI = 30 kg·m²

A flywheel with a moment of inertia of 30 kg·m² spins at 900 rpm. A brake applies a constant friction torque of 50 N·m. How many revolutions N does the flywheel make before it stops?

I = 30 kg·m²n = 900 rpmTb = 50 N·m
N = rev
4.Medium
ω = ?4.5 kgL = 0.9 mm = 1 kg

A uniform slender rod of mass 1 kg and length 0.9 m is pinned at one end and released from rest in a horizontal position. A small ball of mass 4.5 kg is fixed to its free end. Ignore friction and use g = 9.81 m/s². Find the angular velocity ω of the rod as it swings through the vertical position.

m = 1 kgL = 0.9 mmball = 4.5 kgg = 9.81 m/s²
ω = rad/s
5.Hard
0.8 m0.15 mn1​ = 55 rpm

A person stands on a frictionless turntable and holds a 5.5 kg dumbbell in each hand, 0.8 m from the axis. The person and turntable alone have a moment of inertia of 2 kg·m² about the axis. They turn at 55 rpm, then pull the dumbbells in to 0.15 m from the axis. Treat the dumbbells as point masses. Find the new speed n2 in rpm.

I0 = 2 kg·m²m = 2 × 5.5 kgr1 = 0.8 mr2 = 0.15 mn1 = 55 rpm
n2 = rpm
6.Hard
θ = 35°as = 2 m

A solid cylinder rolls without slipping down a slope inclined at 35° to the horizontal. Use g = 9.81 m/s². It starts from rest. How long t does it take to roll 2 m down the slope?

θ = 35°I = ½·m·r²g = 9.81 m/s²s = 2 m
t = s

Answer key

  1. 1. IO = 2.647 kg·m²
  2. 2. t = 7.037 s
  3. 3. N = 424.1 rev
  4. 4. ω = 4.749 rad/s
  5. 5. n2 = 221.2 rpm
  6. 6. t = 1.033 s

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