Rigid-body rotation worksheet with answers

Free printable Rigid-body rotation worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
k = 0.1 m0 → 1100 rpm70 kg

A flywheel of mass 70 kg with a radius of gyration of 0.1 m is accelerated uniformly from rest to 1100 rpm. The driving torque is a constant 3 N·m and friction can be ignored. How long t does this take?

m = 70 kgk = 0.1 mn1 = 0 rpmn2 = 1100 rpmT = 3 N·m
t = s
2.Easy
k = 0.35 mn = 2700 rpm220 kg

A flywheel of mass 220 kg has a radius of gyration of 0.35 m about its axis. It spins at 2700 rpm. Find its kinetic energy Ek in kJ.

M = 220 kgk = 0.35 mn = 2700 rpm
Ek = kJ
3.Medium
v = ?5 kgL = 1.2 mm = 3 kg

A uniform slender rod of mass 3 kg and length 1.2 m is pinned at one end and released from rest in a horizontal position. A small ball of mass 5 kg is fixed to its free end. Ignore friction and use g = 9.81 m/s². Find the speed v of the free end as the rod swings through the vertical position.

m = 3 kgL = 1.2 mmball = 5 kgg = 9.81 m/s²
v = m/s
4.Medium
0 → 2800 rpmI = 39.5 kg·m²

A motor brings a flywheel with a moment of inertia of 39.5 kg·m² from rest up to 2800 rpm in 59 s. Ignoring losses, find the average power Pavg it delivers, in kW.

I = 39.5 kg·m²n = 2800 rpmt = 59 s
Pavg = kW
5.Hard
disc: 6 kgring: 1 kgn1​ = 150 rpm

A uniform solid disc (mass 6 kg, radius 0.2 m) spins freely at 150 rpm about a vertical frictionless shaft. A thin ring of mass 1 kg and the same radius is dropped onto it from rest, centred on the shaft, and the two quickly spin together. How much kinetic energy ΔE is lost in the process?

Mdisc = 6 kgMring = 1 kgR = 0.2 mn1 = 150 rpm
ΔE = J
6.Hard
1.5 m/sω

A solid sphere of mass 13 kg rolls without slipping at 1.5 m/s. What percentage p of its total kinetic energy is rotational?

m = 13 kgv = 1.5 m/sI = (2/5)·m·r²
p = %

Answer key

  1. 1. t = 26.88 s
  2. 2. Ek = 1077 kJ
  3. 3. v = 5.05 m/s
  4. 4. Pavg = 28.78 kW
  5. 5. ΔE = 3.701 J
  6. 6. p = 28.57 %

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